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2 years ago

Please help as soon as possible

Mathematics

2 answers:

kolbaska11 [484]2 years ago

6 0

First -3.7 then 12/20 and lastly 330%

Gemiola [76]2 years ago

4 0

-3.7, 12/20, and 330%

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Need help pls .......

sukhopar [10]

Answer:

It should be the last one because rigid transformations doesn't change in size just where it is

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3 years ago

Which steps could be used to solve this story problem? Krissy had 32 bagels. She gave an equal number of bagels to each child. T

Elina [12.6K]

D, because it said that Krissy had equally distributed the bagels to each child, so 32/8=4, and then it asked how many bagels did the girls get all together, so it's 4x3=12

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3 years ago

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Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?

photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

$D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6$

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

$T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326$

What is the probability that they are both queens?

$P = \frac{D}{T} = \frac{6}{1326} = 0.0045$

0.45% probability that they are both queens.

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3 years ago

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Answer: 253.5

Step-by-step explanation:

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3 years ago

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trasher [3.6K]

Answer:

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Step-by-step explanation:

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3 years ago