1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AnnZ [28]
3 years ago
14

For cheerleading practice, Kiara must be able to lift her legs so that they are parallel to her outstrached arms. For each side

of her body, what is the relationship between the angle formed by her arms and the floor and the angle formend bt her legs and the floor?
Mathematics
1 answer:
podryga [215]3 years ago
5 0
If this is the dance position you are describing, then the arm and the leg of the dancer both make "right" angles (90º angles) to the floor.
You might be interested in
Evaluate the expression when x=3 and y=5 2xy
bija089 [108]

Answer:

30

Step-by-step explanation:

Substitute for x and y

2 x 3 x 5 = 6 x 5 = 30


I hope this helped and please mark mark me as brainliest!

7 0
2 years ago
Read 2 more answers
Joe can cut and split a cord of firewood in 3 fewer hours than Dwight can. When they work​ together, it takes them 2 hours. How
aalyn [17]

Answer:

Dwight will take 6 hours to finish the job alone and Joe will take 3 hours to finish the job alone.

Step-by-step explanation:

Let us assume the time taken by Dwight to split a cord of firewood  = K hrs

So, the per hour rate of Dwight  = (\frac{1}{K})

As, Joe uses 3 LESS hours then Dwight.

So, the time taken by Joe to split a cord of firewood  = (K- 3) hrs

So, the per hour rate of Joe  = (\frac{1}{K-3})

Now, when both of them wok together, it takes them 2 hours.

So, the per hour rate of BOTH of them  = (\frac{1}{2})

⇒ Per hour rate of ( Dwight  + Joe)  =(\frac{1}{2} )

\implies (\frac{1}{K}) +  (\frac{1}{K-3}) = (\frac{1}{2})

Now, solving for the value of K , we get:

(\frac{1}{K}) +  (\frac{1}{K-3}) = (\frac{1}{2})\\\implies  \frac{(K-3) + K}{K (K-3)}  = (\frac{1}{2})\\\implies 2(2K -3) = K^2 - 3K\\\implies k^2 - 3K -4K +6 = 0\\\implies K^2 - 7K  + 6=  0\\\implies K^2 - 6K - K  + 6=  0\\\implies K(K-6) -1(K - 6)=  0\\\implies (K-6)(K-1) = 0

Implies either K = 6 Or K = 1

But if K = 1, (K-3)  = 1- 3  = -2 hours would be A CONTRADICTION.

⇒ K  = 6 hours

Hence, Dwight will take 6 hours to finish the job alone and Joe will take (k-3) = (6-3) = 3 hours to finish the job alone.

8 0
2 years ago
PLEASE HELP I WILL GIVE YOU BRAINLIEST
WARRIOR [948]

Answer:

yoo echo stop deleting my answers  bro

Step-by-step explanation:

4 0
2 years ago
In MATHEMATICS ...write the empirical formula.​
Zepler [3.9K]

Answer:

3Median = Mode + 2Mean

Step-by-step explanation:

8 0
2 years ago
What are the degrees of the missing angles?<br> O 30-60<br> O 90-30<br> 45-45<br> 20-80
ycow [4]

Answer:

a

Step-by-step explanation:

What are the degrees of the missing angles

3 0
3 years ago
Other questions:
  • On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapid
    8·1 answer
  • Can someone please help me out thanks (it's Math , Volume )
    14·1 answer
  • Find the volume of the solid in the first octant bounded by the coordinate planes, the cylinder X^2+Y^2=4 and the plane X+Z=4.
    5·1 answer
  • What is the value of expressions ? 18-2×(4+3)
    12·2 answers
  • What is the value of x given that figure PTRA is an isosceles trapezoid ?! Please help !
    7·2 answers
  • bob has 64 cups. could he distribute them into 6 equally in stacks and not have any left over? Explain
    9·1 answer
  • A flowerpot has a circular base with a diameter of 27 centimeters. Find the circumference of the base of the flowerpot. Round to
    12·1 answer
  • Which equations are correct?
    5·1 answer
  • A 4-- pounds bag of chocolate bars cost $16.24. What is the unit price
    12·1 answer
  • The cost (in dollars) of a basic music streaming service for m months
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!