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alexandr1967 [171]
3 years ago
11

Helpp pls i need this asap

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
5 0
Tommy’s class rank dropped 10 %
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The ordered pairs (1, 1), (2, 8), (3, 27), (4, 64), and (5, 125) represent a function. What is a rule that represents this funct
Zarrin [17]
The functions would be:

D. y=x³

We can check it out.

(1,1); x=1; y=1 ⇒1=(1)³=1*1*1=1
(2,8); x=2; y=8 ⇒8=(2)³=2*2*2=8
(3,27); x=3; y=27 ⇒27=3³=3*3*3=27
(4,64): x=4; y=64 ⇒64=4³=4*4*4=64
(5,125); x=5; y=125 ⇔ 125=5³=5*5*5=125
8 0
3 years ago
What is 0.363 rounded to the nearest tenth
erastovalidia [21]
.4 is the answer m8

............................................................................................................................
6 0
3 years ago
Find the derivative of sinx/1+cosx, using quotient rule​
Mrrafil [7]

Answer:

f'(x) = -1/(1 - Cos(x))

Step-by-step explanation:

The quotient rule for derivation is:

For f(x) = h(x)/k(x)

f'(x) = \frac{h'(x)*k(x) - k'(x)*h(x)}{k^2(x)}

In this case, the function is:

f(x) = Sin(x)/(1 + Cos(x))

Then we have:

h(x) = Sin(x)

h'(x) = Cos(x)

And for the denominator:

k(x) = 1 - Cos(x)

k'(x) = -( -Sin(x)) = Sin(x)

Replacing these in the rule, we get:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2}

Now we can simplify that:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2} = \frac{Cos(x) - Cos^2(x) - Sin^2(x)}{(1 - Cos(x))^2}

And we know that:

cos^2(x) + sin^2(x) = 1

then:

f'(x) = \frac{Cos(x)- 1}{(1 - Cos(x))^2} = - \frac{(1 - Cos(x))}{(1 - Cos(x))^2} = \frac{-1}{1 - Cos(x)}

4 0
3 years ago
x bought a cow for 42000 and was given a discount of 16 percent how much money would have been the discount had she bought the c
Alborosie

Answer:8% discount will be given

Step-by-step explanation:

3 0
3 years ago
Find the Area of the figure below,
murzikaleks [220]

Answer:

169.1 unit^2 to the nearest tenth.

Step-by-step explanation:

Area of the parallelogram = base * height

= 24 * 6 unit^2.

Area of the semicircle = 1/2 pi r^2.

Here r = 1/2 * 8 = 4.

So the area is 1/2 * pi * 4^2

= 8pi unit^2.

The area of the whole figure = 24*6 + 8pi

= 169.13 unit^2.

3 0
2 years ago
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