What is the formula for finding the Volume of a cylinder?

Mathematics

2 answers:

Llana [10]3 years ago

8 0

Answer:

V = πr²h

Step-by-step explanation:

tino4ka555 [31]3 years ago

7 0

Answer:

V = Bh or what the guy above/below me said

Step-by-step explanation:

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Please I need to know how to do this !!

Whitepunk [10]

$\frac{6xyz}{2xy-y}.\frac{2x^{2}-7x+3 }{3xz - 9z} = 2x$

<h3>How to simplify an expression?</h3>

The expression can be simplified as follows:

$\frac{6xyz}{2xy-y}.\frac{2x^{2}-7x+3 }{3xz - 9z}$

Hence,

$\frac{6xyz}{y(2x-1)}.\frac{(x-3)(2x-1)}{3z(x-3)}$

Therefore.

$\frac{6xyz}{y(2x-1)}.\frac{(2x-1)}{3z}$

Hence,

$\frac{2xy}{y(2x-1)}.\frac{(2x-1)}1=2x$

learn more on expression here: brainly.com/question/403991

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2 years ago

Lamar is writing a coordinate proof to show that a segment from the midpoint of the hypotenuse of a right triangle to the opposi

Zanzabum

1. N is a midpoint of the segment KL, then N has coordinates

$\left(\dfrac{x_K+x_L}{2},\dfrac{y_K+y_L}{2} \right) =\left(\dfrac{0+2a}{2},\dfrac{2b+0}{2} \right) =(a,b).$

2. To find the area of △KNM, the length of the base MK is 2b, and the length of the height is a. So an expression for the area of △KNM is

$A_{KMN}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2b\cdot a=ab.$

3. To find the area of △MNL, the length of the base ML is 2a and the length of the height is b. So an expression for the area of △MNL is

$A_{MNL}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2a\cdot b=ab.$

4. Comparing the expressions for the areas you have that the area $A_{KMN}$ is equal to the area $A_{MNL}$ . This means that the segment from the midpoint of the hypotenuse of a right triangle to the opposite vertex forms two triangles with equal areas.