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s344n2d4d5 [400]
3 years ago
10

What is the perimeter of 2 m 10 cm and 45 cm

Mathematics
1 answer:
Papessa [141]3 years ago
8 0
57 cm is the perimeter causd all you do is add the outside and alll you have to do is add those numbers
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Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total
g100num [7]

Answer:

  • 7 first class
  • 9 coach

Step-by-step explanation:

Let f represent the number of first-class tickets that Sarah bought. Then she bought (16-f) coach tickets. Her total spending for airfare was ...

  1140f +160(16-f) = 9420

  980f +2560 = 9420 . . . . simplify

  980f = 6860 . . . . . . . . subtract 2560

  f = 7 . . . . . . . . . . . . . divide by 980; number of first-class tickets

  (16-f) = 9 . . . . . coach tickets

Sarah bought 7 first-class tickets and 9 coach tickets.

6 0
2 years ago
Find the modulus if the complex number 6-8i
NikAS [45]

|a+bi|=\sqrt{a^2+b^2}

|6-8i|=\sqrt{6^2+(-8)^2}=\sqrt{36+64}=\sqrt{100}=10

6 0
1 year ago
Find the volume for the regular pyramid.<br><br> V =
kakasveta [241]

Answer:

Volume=\frac{16\sqrt{2} }{3}units^{3}

Step-by-step explanation:

∵ The volume of the pyramid = 1/3 base area  × height

∵ The base is equilateral Δ with side length 4

∴ The area of the bast = 1/4 × 4² × √3 = 4√3 units²

To get the height of the pyramid draw it from the vertex of the top of the pyramid ⊥ to the base on the centro-id of the base which divides the height of the triangle two ratio 2:1 from the vertex of the triangle

∵ The height of the base = √(4² - 2²) =√12 = 2√3

∴ 2/3 the height = 4√3/3 ⇒ (2:1 means 2/3 from the height)

∴ The height of the pyramid = √[4² - (4√3/3)²] = √[16 - 48/9]

∴ h = 4√2/√3 (4√6/3 in its simplest form)

∴ V = 1/3 × 4√3 × 4√2/√3 = 16√2/3 units³

∴ V = \frac{16\sqrt{2} }{3}

6 0
3 years ago
Read 2 more answers
Place value
s344n2d4d5 [400]

Expanded Notation:

A. 654.362 = (6x100) + (5x10) + (4x1) + (3x0.1) + (6x0.01) + (2x0.001)

B. 125.384 = (1x100) + (2x10) + (5x1) + (3x0.1) + (4x0.01) + (8x0.001)

8 0
3 years ago
Read 2 more answers
The store employees held a frog leaping contest. Frog #1 jumped a distance of 8 feet 3 inches. Frog #2 jumped 2 yards 36 inches.
Alexandra [31]

Answer:

Frog 1 - 8 feet 3 inches =

8 feet x (1 yard/3 feet) = 2.667 Yards

3 inches x (1 foot /12 inches) x ( 1 yard / 3 feet) = 0.83 yards

So Frog 1 = 2.75 Yard

Frog 2 - 2 yards 36 inches

36 inches x (1 foot /12 inches) x (1 yard / 3 feet) = 1 Yard

So Frog 2 = 3 yards

Frog 2 won

It won by 3 - 2.75 = 0.25 Yards

0.25 yards x (3 feet / 1 yard) = 0.75 feet

0.75 feet x (12 inches /1 foot) = 9 inches

<u>So Frog 2 won by 9 inches</u>

8 0
3 years ago
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