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2 years ago

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2 triangles. One triangle has side lengths x, 3 units, 4 units. The other triangle has side lengths 11 units, y, 8 units. The tw

o figures are the image and pre–image of a dilation. Find the lengths of the missing sides. x = units, y = units

1 answer:

attashe74 [19]2 years ago

6 0

Answer:

5.5 and 6

Step-by-step explanation:

i got it wrong and it told me this was the correct answer

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-5(a + 3) = -55<br> What is the value of a?

Kobotan [32]

Answer:

a=8

Step-by-step explanation:

-5(a+3)=-55

First you times the bracket by -5

-5a-15=-55

Then you add the 15 to -55 because since the 15 is a negative on the right it has to be the opposite to the left

-5a=-40

Then you divide both sides by negative 5

-5a . = . -40

--------- ----------

- 5 -5

a= 8

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4 years ago

Find the y-coordinate of the y-intercept of the polynomial function defined below f(x)=2x(x^2+3)

laila [671]

Answer:

y-intercept is (0,0). Mark brainliest?

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3 years ago

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two towers labeled Tower A and Tower B some distance apart and a fire image at a certain distance from both towers Towers A and

astra-53 [7]

Answer:

7.0 mi

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle C

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

$A+B+C=180^o$

substitute the given values

$42^o+64^o+C=180^o\\C=180^o-106^o=74^o$

step 2

Find the measure of a

Applying the law of sines

$\frac{c}{sin(C)}=\frac{a}{sin(A)}$

substitute the given values

$\frac{10}{sin(74^o)}=\frac{a}{sin(42^o)}$

solve for a

$a=\frac{10}{sin(74^o)}sin(42^o)\\a=7.0\ mi$

8 0

3 years ago

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Find the absolute maximum and absolute minimum values of f on the given interval.

anyanavicka [17]

The question is missing parts. Here is the complete question.

Find the absolute maximum and absolute minimum values of f on the given interval.

$f(x)=xe^{-\frac{x^{2}}{32} }$ , [ -2,8]

Answer: Absolute maximum: f(4) = 2.42;

Absolute minimum: f(-2) = -1.76;

Step-by-step explanation: Some functions have absolute extrema: maxima and/or minima.

<u>Absolute</u> <u>maximum</u> is a point where the function has its greatest possible value.

<u>Absolute</u> <u>minimum</u> is a point where the function has its least possible value.

The method for finding absolute extrema points is

1) Derivate the function;

2) Find the values of x that makes f'(x) = 0;

3) Using the interval boundary values and the x found above, determine the function value of each of those points;

4) The highest value is maximum, while the lowest value is minimum;

For the function given, absolute maximum and minimum points are:

$f(x)=xe^{-\frac{x^{2}}{32} }$

Using the product rule, first derivative will be:

$f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} )$

$f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} )$ = 0

$1-\frac{x^{2}}{16}=0$

$\frac{x^{2}}{16}=1$

$x^{2}=16$

x = ±4

x can't be -4 because it is not in the interval [-2,8].

$f(-2)=-2e^{-\frac{(-2)^{2}}{32} }=-1.76$

$f(4)=4e^{-\frac{4^{2}}{32} }=2.42$

$f(8)=8e^{-\frac{8^{2}}{32} }=1.08$

Analysing each f(x), we noted when x = -2, f(-2) is minimum and when x = 4, f(4) is maximum.

Therefore, absolute maximum is f(4) = 2.42 and

absolute minimum is f(-2) = -1.76

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3 years ago

4/7m = 2/7( 2m+1 )<br> What is M?<br> Check Solution

aev [14]

4/7m = 2/7(2m + 1)
4/7m = 4/7m + 2/7
4/7m - 4/7m = 2/7
0 = 2/7 (incorrect)

no solution

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3 years ago

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