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irinina [24]
2 years ago
8

I need help Simplify the expression 63 + 5(4 − 2). 28 36 226 234

Mathematics
1 answer:
DerKrebs [107]2 years ago
6 0

Answer:

226

Step-by-step explanation:

Given:

Simplify 6^3+5(4-2)

Note:

I think you meant 6^3 because if you solve 63+5(4-2):

63+5(4-2)

63+5 * 2

63 + 10

73
Solve:

6^3 + 5(4 - 2 )    

6^3 + 5 x 2

6 x 6 x 6 = 216

226 + 5 x 2

5 x 2 = 10

216 + 10 = 226

<u><em>~Lenvy~</em></u>

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The interior angles of a triangle have measures k°, 27°, and 10°. What is the value of k? Enter your answer in the box.
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To find the measure of the third angle you should keep in mind the following:
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Find S9, the sum of the geometric series to the 9th term, in which a3=3.645 and a8=15
ArbitrLikvidat [17]

Answer:

The sum of the first nine terms of the sequence is 74.44.

Step-by-step explanation:

Geometric sequence concepts:

The nth term of a geometric sequence is given by the following equation.

a_{n+1} = ra_{n}

In which r is the common ratio.

This can be expanded for the nth term in the following way:

a_{n} = a_{1}r^{n-1}

In which a_{1} is the first term.

Or even:

a_{n} = a_{m}r^{n-m}

The sum of the first n terms of a geometric sequence is given by:

S_{n} = \frac{a_{1}(1 - r^{n})}{1 - r}

Finding the common ratio:

a_{3} = 3.645, a_{8} = 15

a_{n} = a_{m}r^{n-m}

a_{8} = a_{3}r^{8-3}

a_{3}r^{5} = a_{8}

3.645r^{5} = 15

r^{5} = \frac{15}{3.645}

r = \sqrt[5]{\frac{15}{3.645}}

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Finding the first term:

a_{3} = a_{1}r^{2}

a_{1} = \frac{a_{3}}{r^{2}}

a_{1} = \frac{3.645}{(1.327)^{2}}

a_{1} = 2.07

Sum of the first nine terms:

S_{9} = \frac{2.07*(1 - (1.327)^{9})}{1 - 1.327} = 74.44

The sum of the first nine terms of the sequence is 74.44.

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