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rusak2 [61]
3 years ago
8

15(d+7)=4(d-4)+11d answer? ​

Mathematics
1 answer:
Viktor [21]3 years ago
6 0

Answer:

Step-by-step explanation:

Factor out to simplify:

15d+105=4d-16+11d

15d+105=15d-16

subtract 15d from both sides

105=-16

this means that there are no solutions for d

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1 + y &lt; 25<br> 101 + 6y &gt; 200
vlada-n [284]

Step-by-step explanation:

i.1+y<25

y<25-1

y<24

ii.101+6y>200

6y>200−101

6y>99

y>99/6

y>33/2

5 0
3 years ago
The perimeter of a field is 120 yards. what is the length and width?
ElenaW [278]
120/4=30. Remember its widthxlength. if you forget ask your teacher or look online for more help. Good luck.
7 0
3 years ago
Pls help this is pretty urgent
KIM [24]

Answer:

(a)  0

(b)  f(x) = g(x)

(c)  See below.

Step-by-step explanation:

Given rational function:

f(x)=\dfrac{x^2+2x+1}{x^2-1}

<u>Part (a)</u>

Factor the <u>numerator</u> and <u>denominator</u> of the given rational function:

\begin{aligned} \implies f(x) & = \dfrac{x^2+2x+1}{x^2-1} \\\\& = \dfrac{(x+1)^2}{(x+1)(x-1)}\\\\& = \dfrac{x+1}{x-1}\end{aligned}

Substitute x = -1 to find the limit:

\displaystyle \lim_{x \to -1}f(x)=\dfrac{-1+1}{-1-1}=\dfrac{0}{-2}=0

Therefore:

\displaystyle \lim_{x \to -1}f(x)=0

<u>Part (b)</u>

From part (a), we can see that the simplified function f(x) is the same as the given function g(x).  Therefore, f(x) = g(x).

<u>Part (c)</u>

As x = 1 is approached from the right side of 1, the numerator of the function is positive and approaches 2 whilst the denominator of the function is positive and gets smaller and smaller (approaching zero).  Therefore, the quotient approaches infinity.

\displaystyle \lim_{x \to 1^+} f(x)=\dfrac{\to 2^+}{\to 0^+}=\infty

5 0
1 year ago
Read 2 more answers
Consider the following set of sample data: (34, 32, 34, 32, 40, 37, 31, 31, 29, 27). We're interested in using this data to test
rosijanka [135]

Answer:

Option I and II

Step-by-step explanation:

I. Assuming this represents a random sample from the population, the sample mean is an unbiased estimator of the population mean.

II. Because they're robust, t procedures are justified in this case.

The t procedures are utilized because they are used as a hypothesis testing tool, which allows for testing of an hypothesis applicable to a population where in this case we are testing the null hypothesis about the population mean.

7 0
3 years ago
Name:
zzz [600]

Answer:

a)1.5

b)36

c)34

d)5.33333...

e)0

Step-by-step explanation:

3 0
2 years ago
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