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Mila [183]
3 years ago
14

A scale model of a ramp is a right triangular prism as given in this figure. in the actual ramp, the triangular base has a heigh

t of 0.5 yards. what is the surface area of the actual ramp, including the underside? enter your answer as a decimal in the box.
Mathematics
1 answer:
kakasveta [241]3 years ago
3 0

The surface area of the actual ramp including the underside is 16.8 ft²

The height of the actual ramp = 1.2 feet  

The height of the model = 6 cm

<h3>What is the surface area of a right triangular prism?</h3>

A right triangular prism is a 3-dimensional triangle with two congruent triangular faces and 3 rectangular faces that connect the triangular.

The surface area of a right triangular prism

= (Perimeter of the base × Length of the prism) + (2 × Base Area)

Scale factor = 1.2 feet / 6 cm = 0.2 ft/cm

Actual base = 16 cm × 0.2 ft/cm = 3.2 ft

convert the units

9 cm = 9 cm × 0.2 ft/cm = 1.8 ft

10 cm = 10 cm × 0.2 ft/cm = 2 ft

The surface area of a right triangular prism

= (Perimeter of the base × Length of the prism) + (2 × Base Area)

Surface area of actual ramp = 2(0.5 × 3.2 ft × 1.2 ft) + 2(2 ft × 1.8 ft) + (1.8 ft × 3.2 ft)

= 16.8 ft²

Hence, the surface area of the actual ramp including the underside is 16.8 ft²

Learn more about the area here:

brainly.com/question/25292087

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F(r) = 3.14r2. what is f(5)?
rjkz [21]

Answer:

f(5)= 78.5. I hope this helps!!

5 0
4 years ago
Please help me! Due soon!
givi [52]

Answer:

70/9

Step-by-step explanation:

We have the quadratic:

3x^2+4x-9

So, let’s find the roots of the quadratic. We will set the expression equal to 0:

3x^2+4x-9=0

Testing for factors, we can see that our quadratic isn’t factorable.

So, we can use the Quadratic Formula. The quadratic formula is given by:

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case:

a=3, b=4,\text{ and } c=-9

Therefore, by substitution:

\displaystyle x=\frac{-(4)\pm\sqrt{(4)^2-4(3)(-9)}}{2(3)}

Evaluate:

\displaystyle x=\frac{-4\pm\sqrt{124}}{6}

Simplify the square root:

\sqrt{124}=\sqrt{4\cdot31}=2\sqrt{31}

Hence:

\displaystyle x=\frac{-4\pm2\sqrt{31}}{6}

Reduce:

\displaystyle x=\frac{-2\pm\sqrt{31}}{3}

So, our roots are:

\displaystyle x_1=\frac{-2+\sqrt{31}}{3}, x_2=\frac{-2-\sqrt{31}}{3}

We want to find the sum of the <em>squares</em> of our two roots. So, let’s square each term:

\displaystyle (x_1)^2=\Big(\frac{-2+\sqrt{31}}{3}\Big)^2

Square. For the numerator, we can use the perfect square trinomial patten where:

(a+b)^2=(a^2+2ab+b^2)

Therefore:

\displaystyle (x_1)^2=\Big(\frac{(-2)^2+2(-2)(\sqrt{31})+(\sqrt{31})^2}{9}\Big)

Simplify:

\displaystyle (x_1)^2=\frac{35-4\sqrt{31}}{9}

Similarly, for the second root, we will have:

\displaystyle (x_2)^2=\Big(\frac{-2-\sqrt{31}}{3}\Big)^2

So:

\displaystyle (x_2)^2=\Big(\frac{(-2)^2+2(-2)(-\sqrt{31})+(-\sqrt{31})^2}{9}\Big)

Simplify:

\displaystyle (x_2)^2=\frac{35+4\sqrt{31}}{9}

Therefore, our sum will be:

\displaystyle (x_1)^2+(x_2)^2\\\\ \begin{aligned} &=\frac{35-4\sqrt{31}}{9}+\frac{35+4\sqrt{31}}{9}\\&=\frac{35-4\sqrt{31}+35+4\sqrt{31}}{9}\\&=\frac{70}{9}\end{aligned}

Therefore, our final answer is 70/9.

3 0
3 years ago
M
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Need to see the picture ..?
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3 years ago
A room has a length of 8 m. A scale diagram is drawn of the room. In the diagram, the room has a length of 1 cm. What is the sca
liberstina [14]

The scale of the diagram as described in the task content is; 1: 8 where k= 8.

<h3>What is the scale of the diagram?</h3>

It follows from the task content that the original length of the room in discuss is 8cm. It therefore follows that the length of the room in the scale diagram is 1cm. On this note, the scale of the diagram in discuss is; 1 : 8 as 1cm on the diagram corresponds to 8cm actual length.

Read more on scale of diagrams;

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#SPJ1

8 0
2 years ago
Which is a perfect square?<br> 072<br> 81<br> 90<br> 99
nikitadnepr [17]

Answer:81

Step-by-step explanation:

9•9 = 81

3 0
3 years ago
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