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mart [117]
3 years ago
10

Given the events below, determine which equation correctly calculates the probability of drawing two kings in a row from a stand

ard 52-card deck, without replacement.
Event A: The first card drawn is a king.
Event B: The second card drawn is a king.

A. P(A n B) = P(A) * P(B|A)

B. P(A n B) = P(A) * P(B)

C. P(A n B) = P(A) * P(A|B)

D. P(A n B) = P(B) * P(B|A)
Mathematics
1 answer:
Tems11 [23]3 years ago
4 0
P of drawing two kings in a row = P of first card is a king * P of second card is a king given that the first card was a king

P (A ∩ B) = P(A) * P(B|A)

Answer: option A.

You can check that this is 4/52 * 3/51
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In Triangle EFG,9 = 12 inches, e = 55 inches and Angle F=75º. Find the area of Triangle EFG, to the
Tresset [83]

9514 1404 393

Answer:

  319 in²

Step-by-step explanation:

The applicable area formula is ...

  A = 1/2(g)(e)·sin(F)

  A = 1/2·(12 in)(55 in)sin(75°) ≈ 319 in²

The area of the triangle is about 319 square inches.

8 0
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6,7,8 what are the inequality’s
yan [13]

Answer:

Its an equation, not an inequality

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3 years ago
Graph x^3-x^2-2x=0 what are the solutions of the equation
Aleks [24]
X^3 - x^2 - 2x = 0
x ( x^2 - x - 2 ) = 0
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7 0
3 years ago
a model of a car is amde to a scale of 1:40. the volume of the model is 45cm^3. calcualte the volume of the car. give your answe
spin [16.1K]

The volume of the car is 1800cm^3 which is equivalent to 0.0018m^3

<h3>Scale modelling</h3>

Given the scale factor that model of a car is amde to a scale of 1:40, Giving that the model as 45cm^3, this means that;

1 = 45cm^2

Determine the volume of the car

40 = x

Find the ratio

1/40 = 45/x

x = 40*45

x = 1800cm^3

x = 0.0018m^3

Hence the volume of the car is 1800cm^3 which is equivalent to 0.0018m^3

Learn more on scale factor here; brainly.com/question/25722260

#SPJ1

6 0
2 years ago
WILL GIVE BRAINLIEST
Amanda [17]

════════ ∘◦❁◦∘ ════════

<h3>Answer : y = ⅚x - 3</h3>

════════════════════

<h3>Known</h3>

x1 = 6

y1 = 2

x2 = (-6)

y2 = (-8)

════════════════════

<h3>Question</h3>

Equation of the line (y = mx + c)

════════════════════

<h3>Way to do</h3>

#First, you find the gradient (m)

m =  \frac{y2 - y1}{x2 - x1}  =  \frac{(( - 8) - 2)}{(( - 6) - 6)}  =  \frac{( - 10)}{( - 12)}  =  \frac{5}{6}

#Now use the formula of equation of the line

y - y1 = m(x - x1)

y - 2 = ⅚(x - 6)

y - 2 = ⅚x - 5

y = ⅚x - 5+2

y = ⅚x - 3

════════════════════

3 0
2 years ago
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