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2 years ago

What is the value of the discriminant for the quadratic equation zero equals 2x^2+x-3

Mathematics

1 answer:

Liono4ka [1.6K]2 years ago

7 0

Discriminant for the quadratic equation $2x^2+x-3=0$ is $d=25$

How to find the d Discriminant of the quadratic equation ?

We know that the standard quadratic equation

$ax^2+bx+c=0$

Discriminant of the equation is $d=b^2-4ac$

Equation given in the question is

$2x^2+x-3=0$

So we can find the values of $a,b,c$

$a=2\\b=1\\c=-3$

Substitute the values

$d=1^2-4*2*(-3)\\d=1+24\\d=25$

Learn more about the discriminant of the quadratic equation here:

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disa [49]

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Step-by-step explanation:

Given

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WE have to determine the lengths of all sides before finding the perimeter and area.

The formula of modulus is:

$d = \sqrt{(x_{2}- x_{1})^{2} +(y_{2}-y_{1})^{2}}\\AB=\sqrt{(16-2)^{2} +(2-8)^{2}}\\=\sqrt{(14)^{2} +(-6)^{2}}\\=\sqrt{196+36}\\ =\sqrt{232}\\=15.23\\\\BC=\sqrt{(6-16)^{2} +(2-2)^{2}}\\=\sqrt{(-10)^{2} +(0)^{2}}\\=\sqrt{100+0}\\ =\sqrt{100}\\=10\\\\AC=\sqrt{(6-2)^{2} +(2-8)^{2}}\\=\sqrt{(4)^{2} +(-6)^{2}}\\=\sqrt{16+36}\\ =\sqrt{52}\\=7.21\\\\$

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