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2 years ago

What is 6(x+?)= 6x + 30 ??????????

Mathematics

1 answer:

Aliun [14]2 years ago

4 0

Answer:

Let y = '?'

6(x + y) = 6x + 30

6x +6y = 6x + 30

6x + 6y - 6x = 6x + 30 - 6x

6y = 30

6y / 6 = 30 / 6

y = 5

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The price of a house increases in value from £149,950 to £182,500

Rufina [12.5K]

Answer is 21.7%

Find difference in price:

182,500 - 149,950 = $32,550

Divide difference by original price:

32,550/149,950 x 100 = 21.71%

6 0

3 years ago

HELP ME PLEASE I NEED A GOOD GRADE

posledela

Answer:

rectangles

Step-by-step explanation:

They are rectangles because all paralellograms have 4 sides and right angles. All objects or shapes with 4 sides and corners, are rectangle. Even squares are catorized as rectangles.

3 0

3 years ago

Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

5 0

3 years ago

An office has area of 120m^2 and it is 12m wide . write an equation to represent the area

vampirchik [111]

10x12=120m^2

120/12=10

3 0

3 years ago

Read 2 more answers

Kayla wants to fence in a rectangular dog pen that is 30 ft by 40 ft How would you use wha

castortr0y [4]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the dimension of the dog pen = 30 ft by 40 ft.

Using the knowledge of geometry, that know that a rectangle has been built, the area of the pen should be :

Area of rectangle = Length * width

Area = 40 * 30

Area = 1200 ft²

Perimeter of rectangle = 2(Length + width)

Perimeter = 2(40 + 30)

Perimeter = 2(70)

Perimeter = 140 feets

Hence, area of the pen should be 1200 ft² and its perimeter or fencing should measure 140 feets

4 0

3 years ago