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Vika [28.1K]
2 years ago
10

Determine if the equation has no solution,one solution, or infinite many solution.

Mathematics
1 answer:
Vladimir [108]2 years ago
3 0

Answer:

Step-by-step explanation:

-2(11-12)=-4(1-6x)​ becomes -2(-1) = -4(1 - 6x)

Next, we divide both sides by -2, obtaining -1 = 2(1 - 6x), and then

                                                                        -1 = 2 -12x, or

                                                                         -3 = -12x

Simplifying this result, we get 1 = 4x, or x = 1/4

We conclude that -2(11-12)=-4(1-6x)​ has ONE solution, which is x = 1/4

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Answer: There are 4 possibilities. They are all listed below with their percents.

You can create a tree diagram to shows all of the possibilities. It will start with 2 branches and then each of those branches will have 2 branches.

The possibilities are:  UU, UD, DU, DD

To find the probabilities of each, you have to multiply the percent for each together.

UU = 0.66 x 0.66 = 0.4356
UD = 0.66 x 0.34 = 0.2244
DU = 0.34 x 0.66 = 0.2244
DD = 0.34 x 0.34 = 0.1156
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3 years ago
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a survey of 1,000 people was done bu the new York times. 80% of the people did not know the name of their representative in Cong
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The answer is 200. you would multiply 1000 by 80% giving you 800. 800 people didnt know the name so that leave 200 people did.
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Find the indicated limit, if it exists. limit of f of x as x approaches 9 where f of x equals x plus 9 when x is less than 9 and
SVEN [57.7K]

Answer:

B. 18

Step-by-step explanation:

For the function

f(x)=\left\{\begin{array}{l}x+9,\ \ x

we can find the value of the function for all x that are very close to 9 but are less than 9 and for all values of x that are very close to 9 but are greater than 9.

1. For x

\lim \limits_{x\rightarrow 9}f(x)=\lim \limits_{x\rightarrow 9}(x+9)=9+9=18

2. For x\ge 9:

\lim \limits_{x\rightarrow 9}f(x)=\lim \limits_{x\rightarrow 9}(27-x)=27-9=18

So, limit exists and is equal to 18.

8 0
3 years ago
A closed box with a square base is to have a volume of 13 comma 500 cm cubed. The material for the top and bottom of the box cos
andrezito [222]

Answer:

x  =  1,5 cm

h  =  6  cm

C(min) = 135 $

Step-by-step explanation:

Volume of the box is :

V(b)  = 13,5 cm³

Aea of the top is equal to area of the base,

Let call  " x " side of the base then as it is square area is A₁ = x²

Sides areas are 4 each one equal to x * h  (where h is the high of the box)

And volume of the box is   13,5 cm³  = x²*h

Then   h  =  13,5/x²

Side area is :  A₂ =  x* 13,5/x²

A(b)  = A₁  + A₂

Total area of the box as functon of x is:

A(x)  = 2*x²  + 4* 13,5 / x

And finally cost of the box is

C(x)  = 10*2*x²   +  2.50*4*13.5/x

C(x)  = 20*x²  +  135/x

Taking derivatives on both sides of the equation:

C´(x)  =  40*x   -  135*/x²

C´(x)  = 0     ⇒      40*x   -  135*/x² = 0    ⇒  40*x³ = 135

x³  = 3.375

x  = 1,5 cm

And   h  =  13,5/x²     ⇒   h  =  13,5/ (1,5)²

h = 6 cm

C(min)  = 20*x²  + 135/x

C(min)  = 45  +  90

C(min)  = 135 $

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Answer:

  The quadratic curve has the best correlation to the given data.

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