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kirza4 [7]
2 years ago
14

A submarine at a depth of -2 2/3 feet descended 5 1/2 feet. How many feet must the submarine rise to reach the surface? Explain

your thinking.

Mathematics
1 answer:
vladimir2022 [97]2 years ago
5 0

Original position of the submarine below the Surface = -2 2/3= -8/3

Submarine at a depth of -2 2/3 feet descended by 5 1/2 feet.

So new position of the Submarine = \frac{-8}{3}-\frac{11}{2}\\\\  = \frac {-16 - 33}{2}\\\\  = \frac{-49}{6}

To Reach the surface submarine must rise = 0-(-49/6)

As seen from the equation the two negative sign [(-)(-)] will change into a positive sign.

At the surface the position of the submarine = +49/6 feet

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