The answer for the question is a
To solve this problem, let us first assign some
variables. Let us say that:
x = pigs
y = chickens
z = ducks
From the problem statement, we can formulate the
following equations:
1. y + z = 30 --->
only chicken and ducks have feathers
2. 4 x + 2 y + 2 z = 120 --->
pig has 4 feet, while chicken and duck has 2 each
3. 2 x + 2 y + 2 z = 90 --->
each animal has 2 eyes only
Rewriting equation 1 in terms of y:
y = 30 – z
Plugging this in equation 2:
4 x + 2 (30 – z) + 2 z = 120
4 x + 60 – 2z + 2z = 120
4 x = 120 – 60
4 x = 60
x = 15
From the given choices, only one choice has 15 pigs. Therefore
the answers are:
She has 15 pigs, 12 chickens, and 18 ducks.
Solving #19
<u>Take y-values from the graph</u>
- a) (g·f)(-1) = g(f(-1)) = g(1) = 4
- b) (g·f)(6) = g(f(6)) = g(2) = 2
- c) (f·g)(6) = f(g(6)) = f(5) = 1
- d) (f·g)(4) = f(g(4)) = f(2) = -2
2x + 3y = 12
I am going to put this in y = mx + b form, where m is ur slope and b is ur y intercept.
2x + 3y = 12
3y = -2x + 12
y = -2/3x + 4......slope is -2/3 and y int is (0,4)
x int can be found by subbing in 0 for y and solving for x
2x + 3y = 12
2x + 3(0) = 12
2x = 12
x = 6.....so x int is (6,0)
start at y int (0,4).....and since the slope is -2/3, come down 2 spaces, and to the right 3 spaces, then down 2 spaces, to the right 3 spaces....keep doing that and u should cross the x axis at (6,0)
Answer:
2 fluid ounces
Step-by-step explanation:
