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grigory [225]
2 years ago
9

Element Molar Mass (g/mol)

Chemistry
2 answers:
Scorpion4ik [409]2 years ago
7 0

The number of moles of ethanol the chemist will use is 0.65 moles.

<h3>What is a mole?</h3>

A mole is the atomic weight of a molecule of chemical in grams

To calculate the number of moles of ethanol the chemist will use, we apply the formula below.

Formula:

  • n = R'/M.............. Equation 1

Where:

  • n = number of moles of ethanol
  • m = mass of ethanol
  • M = molar mass of ethanol

From the question,

Given:

  • R' = 30 g
  • M = [(12.01)+(1.01×3)+(12.01)+(1.01×2)+(16.0)+(1.01)] = 46.08 g/mol

Substitute these values into equation 1

  • n = 30/46.08
  • n = 0.65 moles.

Hence, The number of moles of ethanol the chemist will use is 0.65 moles.

Learn more about moles here: brainly.com/question/15356425

artcher [175]2 years ago
6 0

The number of moles of ethanol the chemist will use in the experiment involving 30g of ethanol is 0.65moles.

<h3>How to calculate number of moles?</h3>

The number of moles of a substance can be calculated by dividing the mass of the substance by its molar mass. That is;

no. of moles = mass ÷ molar mass

According to this question, a chemist will use a sample of 30 g of ethanol (CH3CH2OH) in an experiment. The number of moles can be calculated as follows:

Molar mass of ethanol = 12(2) + 1(5) + 17 = 46g/mol

no of moles = 30g ÷ 46g/mol

no. of moles = 0.65moles

Therefore, the number of moles of ethanol the chemist will use in the experiment involving 30g of ethanol is 0.65moles.

Learn more about moles at: brainly.com/question/1458253

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Alum is a compound used in a variety of applications including cosmetics, water purification, and as a food additive. It can be
vlabodo [156]

Answer:

The theoretical yield of alum is 19.873 grams and percent yield for this alum synthesis is 45.33%.

Explanation:

Mass of bottle = 10.221 g

Mass of bottle with aluminium pieces = 11.353 g

Mass of aluminium = 11.353 g - 10.221 g = 1.132 g

Mass of alum and bottle = 19.230 g

Mass of alum =  19.230 g - 10.221 g = 9.009 g

Experimental yield of alum =  9.009 g

Theoretical yield of alum:

2Al(s) +2 KOH(aq) +4H_2SO_4(aq)+10 H_2O(l) \rightarrow 2 KAl(SO_4)_2.12 H_2O(s)+3H_2(g)

Moles of aluminium = \frac{1.132 g}{27 g/mol}=0.041926 mol

According to reaction, 2 moles of aluminum gives 2 moles of alum.

Then 0.041926 mol aluminium will give :

\frac{2}{2}\times 0.041926 mol=0.041926 mol of alum.

Mass of 0.041926 moles of alum:

0.041926 mol × 474 g/mol= 19.873 g

Theoretical yield of alum = 19.873 g

Percentage yield:

\% Yield =\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Percentage yield of the alum:

\% Yield =\frac{ 9.009 g}{19.873 g}\times 100=45.33\%

The theoretical yield of alum is 19.873 grams and percent yield for this alum synthesis is 45.33%.

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What is required for electrons to move from the stable energy level to an excited state?
Gekata [30.6K]

answer

When an electron temporarily occupies an energy state greater than its ground state, it is in an excited state. An electron can become excited if it is given extra energy, such as if it absorbs a photon, or packet of light, or collides with a nearby atom or particle

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Explain how acids and bases directly or indirectly affect the hydrogen ion concentration of a solution.
ehidna [41]

By taking hydrogen ions, certain bases directly lower the H+ than OH- concentration. Other bases break down to create hydroxide ions, which indirectly lowers the H+ concentration.

<h3>What is the difference between acid and base?</h3>

H+ ion concentration is raised by an acid. A base is a chemical that, in an aqueous solution, produces hydroxide (OH-) ions, gives electrons, and receives protons. A donor of protons is an acid. A proton can enter a base. When dissolved in water, an acidic chemical compound produces a solution that has more H+ ion activity than clean water. A base is an aqueous material that releases hydroxide (OH-) ions, receives protons, or contributes electrons. A donor of protons is an acid. A base is a proton acceptor.

To learn more about acid and base, visit:

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Oxidation number of phosphorus in calcium phosphorus oxides whole 2
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Example Ca3(PO4)2
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Determine the length of the object shown. 7 cm 7.2 cm 72.5 mm 72.50 mm
jekas [21]

Answer:

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Explanation: its not 7 because it starts before 1 not on 1 (i cant remember the answer but sorry if its wrong

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