Answer:
Terms in this set (13)
Hydroxide. OH.
Nitrate. NO3.
Ammonium. NH4.
Bicarbonate/Hydrogen Carbonate. HCO3.
Bisulphate. HSO4.
Chlorate. ClO3.
<h2>hope it's correct</h2>
Answer:
2–butyne.
Explanation:
To name the compound given above, we must determine the following:
1. Determine the functional group of the compound.
2. Determine the longest continuous carbon chain. This gives the parent name of the compound.
3. Locate the position of the functional group by giving it the lowest possible count.
4. Combine the above to obtain the name.
Thus, we shall name the compound as follow:
1. The compound contains triple bond (C≡C). Therefore, the compound is an alkyne.
2. The longest chain is carbon 4. Thus the parent is butyne.
3. The triple bond (C≡C) is located at carbon 2 when we count from either side.
4. The name of the compound is:
2–butyne
The giant piles of mining waste called tailings. These wastes consists of ground rock and process effluents from a mining plant. These wastes are stored on a surface either in a facility or in the form of piles. Also, sometimes it is stored underground in areas that are mined out.
First, we need to convert the grams of gold into mole using the molar mass (molecular weight) of gold, and then into particles using avogadro's number (1 mol= 6.02 x 10^23)
molar mass of gold= 197 grams/ mole
100.0 grams (1 mole/ 197 grams) x (6.02 x 10^23 particles/ 1 mole) = 3.06 x 10^23
