All categories

3 years ago

PLEASE ANSWER QUICKLYY IK ITS TEDIOUS CUZ THERES A LOT BUT MATH EXPERTS, HELP

Mathematics

1 answer:

AlexFokin [52]3 years ago

5 0

Step-by-step explanation:

i answered these 3 already.

You might be interested in

Based on data from the 1980 Census the average age of a Na'alehu County, Hawaii resident is 39 years with a standard deviation o

Trava [24]

Answer:

yes

Step-by-step explanation:

6 0

3 years ago

HELP PLEASE!!!

monitta

It is divided by 2 each time, and so your next number will be 4, since 8/2 = 4

C) 4

hope this helps :D

7 0

4 years ago

Find the range of 5,3,1,1,3,3,4,4,4,1,1,4,2,2,5,5,5,2,5,5

ExtremeBDS [4]

Answer: 4

find the largest number (5) and take away the smallest (1)

5-1=4

6 0

3 years ago

please solve the question and show your work so which property allows the order of numbers to be switched without changing the a

olga_2 [115]

This is called the commutative property (ies).
Search the commutative property of Multiplication, addition, etc...

4 0

4 years ago

A tank holds 300 gallons of water and 100 pounds of salt. A saline solution with concentration 1 lb salt/gal is added at a rate

Shkiper50 [21]

The amount of salt in the tank changes with rate according to

$Q'(t)=\left(1\dfrac{\rm lb}{\rm gal}\right)\left(4\dfrac{\rm gal}{\rm min}\right)-\left(\dfrac{Q(t)}{300+(4-1)t}\dfrac{\rm lb}{\rm gal}\right)\left(1\dfrac{\rm gal}{\rm min}\right)$

$\implies Q'+\dfrac Q{300+3t}=4$

which is a linear ODE in $Q(t)$ . Multiplying both sides by $(300+3t)^{1/3}$ gives

$(300+3t)^{1/3}Q'+(300+3t)^{-2/3}Q=4(300+3t)^{1/3}$

so that the left side condenses into the derivative of a product,

$\big((300+3t)^{1/3}Q\big)'=4(300+3t)^{1/3}$

Integrate both sides and solve for $Q(t)$ to get

$(300+3t)^{1/3}Q=(300+3t)^{4/3}+C$

$\implies Q(t)=300+3t+C(300+3t)^{-1/3}$

Given that $Q(0)=100$ , we find

$100=300+C\cdot300^{-1/3}\implies C=-200\cdot300^{1/3}$

and we get the particular solution

$Q(t)=300+3t-200\cdot300^{1/3}(300+3t)^{-1/3}$

$\boxed{Q(t)=300+3t-2\cdot100^{4/3}(100+t)^{-1/3}}$

5 0

3 years ago