PLEASE ANSWER QUICKLYY IK ITS TEDIOUS CUZ THERES A LOT BUT MATH EXPERTS, HELP

Recently, a random sample of 13-18 year olds was asked, "How much do you currently have in savings?" The data in the table re

Sonbull [250]

Answer:

μ = 235.38

σ = 234.54

Step-by-step explanation:

Assuming the table is as follows:

$\left[\begin{array}{cc}Savings&Frequency\\\$0-\$199&339\\\$200-\$399&86\\\$400-\$599&55\\\$600-\$799&18\\\$800-\$999&11\\\$1000-\$1199&8\\\$1200-\$1399&3\end{array}\right]$

This is an example of grouped data, where a range of values is given rather than a single data point. First, find the total frequency.

n = 339 + 86 + 55 + 18 + 11 + 8 + 3

n = 520

The mean is the expected value using the midpoints of each range.

μ = (339×100 + 86×300 + 55×500 + 18×700 + 11×900 + 8×1100 + 3×1300) / 520

μ = 122400 / 520

μ = 235.38

The variance is:

σ² = [(339×100² + 86×300² + 55×500² + 18×700² + 11×900² + 8×1100² + 3×1300²) − (520×235.38²)] / (520 − 1)

σ² = 55009.7

The standard deviation is:

σ = 234.54

6 0

3 years ago

Henry bought 1/4 pounds of screws and 2/5 of backstop build a skateboard ramp. What is the total weight of the screws and nails

nexus9112 [7]

It equals 0.65 pounds

6 0

3 years ago

chloe has 42 oranges 24 apples and 18 bananas to put into fruit baskets each fruit will be divided equally so each basket will h

Nimfa-mama [501]

We want to calculate the number of baskets to which chloe can make.

Note that we have 42 oranges, 24 apples and 18 bananas, and since we are splitting them into the number of baskets, it must happen that the each number is a multiple of the number of baskets.

We will check each option to find out if the numbers are a multiple of the number. Then we will take the greatest to number to which all of them are a multiple.

Case 2: Note that 42= 21*2, 24=12*2 and 18 = 9*2 so all of them are multiples of 2.

So, so far the greatest number is 2.

Case 3:

Note that 42 = 3*14, 24 = 8*3 and 18 = 6*3. So all of them are multiples of 3.

So, so far the greatest number is 3.

Case 6:

Note that 42 = 6*7, 24 = 6*4 and 18 = 6*3. So all of them are multiples of 3. So, so far the greatest number is 6.

Case 8:

Note that 24=8*3. But neither 18 o 42 are multiples of 8. So, this can't be an option.

So, this means that the most number of fruit baskets Chole can make is 6, since 6 divides evenly all three numbers (42,24 and 18)

3 0

1 year ago