9514 1404 393
Answer:
4a. ∠V≅∠Y
4b. TU ≅ WX
5. No; no applicable postulate
6. see below
Step-by-step explanation:
<h3>4.</h3>
a. When you use the ASA postulate, you are claiming you have shown two angles and the side between them to be congruent. Here, you're given side TV and angle T are congruent to their counterparts, sides WY and angle W. The angle at the other end of segment TV is angle V. Its counterpart is the other end of segment WY from angle W. In order to use ASA, we must show ...
∠V≅∠Y
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b. When you use the SAS postulate, you are claiming you have shown two sides and the angle between them are congruent. The angle T is between sides TV and TU. The angle congruent to that, ∠W, is between sides WY and WX. Then the missing congruence that must be shown is ...
TU ≅ WX
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<h3>5.</h3>
The marked congruences are for two sides and a non-included angle. There is no SSA postulate for proving congruence. (In fact, there are two different possible triangles that have the given dimensions. This can be seen in the fact that the given angle is opposite the shortest of the given sides.)
"No, we cannot prove they are congruent because none of the five postulates or theorems can be used."
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<h3>6.</h3>
The first statement/reason is always the list of "given" statements.
1. ∠A≅∠D, AC≅DC . . . . given
2. . . . . vertical angles are congruent
3. . . . . ASA postulate
4. . . . . CPCTC
Answer:
h(2) = 1
Step-by-step explanation:
2^2 is 4. 5(2) is 10. now we have 4 - 10 + 7. -6 + 7 = 1.
Answer:
x=6
Step-by-step explanation:
this is a property
(8x-4)+(3x+17)=17x-23
11x+13=17x-23
23+13=6x
36=6x
x=6
Add 25.5, 15.3, 9.25 all together and subtract it from 72. The answer is 21.95
Answer:
b) μ = 2 and σ = 1.29
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given that the A spinner is divided into six equal-sized sectors labelled 1 through 6</em>
<em>Given that the probability of labelled '1'</em>
<em> </em>
=0.16
<em> q = 1-p = 1- 0.16 = 0.84</em>
Let 'X' be a random variable in binomial distribution
The mean of the binomial distribution
μ = n p
μ =
<em>The mean of the binomial distribution = 2</em>
<u><em>Step(ii):-</em></u>
The standard deviation of X
σ 
σ = 
σ = 
<em>The standard deviation of the binomial distribution</em>
<em> </em> σ = 
<u><em></em></u>
<u><em></em></u>