Answer:
None of the above
Step-by-step explanation:
Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval:
(-15,-10).
<h3>What is the slope of the tangent line to a function f(x) at point x = x0?</h3>
It is given by the derivative at x = x0, that is:
.
In this problem, the function is:

Hence the derivative is:

For a slope of -1, we have that:
0.4x + 5 = -1
0.4x = -6
x = -15.
For a slope of 1, we have that:
0.4x + 5 = 1.
0.4x = -4
x = -10
Hence the interval is:
(-15,-10).
More can be learned about derivatives and tangent lines at brainly.com/question/8174665
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9514 1404 393
Answer:
d. 14 -3x
Step-by-step explanation:
If you want to substitute for y in the second equation, you must use the first equation to find an expression for y.
3x +y = 14 . . . . . . first equation
y = 14 -3x . . . . . . subtract 3x from both sides
This gives you the expression for y that you want to use for substitution. It matches the expression of choice D.
y = 14 -3x . . . . matches D
8.5b.
7a= 5a +3b
-5a -5a
2a = 3b
/2
a= 1.5b
Solve by substitution and you get;
8.5b=8.5b
Because of the lack of constants in the equation there isn't a definite answer.
228/28 1/2 ÷ 4 3/4 = 57/2 × 4/19= 228/38 = 6
Btw i did keep change flip