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vazorg [7]
2 years ago
7

Use the distributive property (expand) to write an equivalent expression for: 3(4x-2t). Type your answer ( I NEED THIS RIGHT AWA

Y PLS)
Mathematics
1 answer:
Eddi Din [679]2 years ago
5 0

Answer:

The distributive property here is to just multiply each value by tree number outside the parenthesis.

3 ( 4x - 2t)

12x - 6t

That would be your answer.

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4.5, 9, 13.5, 18...
Sladkaya [172]

Answer:

a) Arithmetic

b) 22.5

c) 4.5

d) a_n = 4.5 + 4.5(n - 1)

e) a_15 = 67.5

Step-by-step explanation:

a) Subtract one term by the term right before it, and the difference will be the common difference.

9 - 4.5 = 4.5

13.5 - 9 = 4.5

18 - 13.5 = 4.5

Therefore, the common difference is 4.5.

b) Since the common difference is 4.5, add 4.5 to the 18 (which was the last value given). The result is 22.5.

c) We have already figured out that the common difference is 4.5.

d) The explicit formula would be a_n = a1 + d(n - 1). The first term is 4.5 and d is also 4.5, so the explicit formula is a_n = 4.5 + 4.5(n-1).

e) Plug 15 into our explicit formula for n. a_15 = 4.5 + 4.5(14). The result is 67.5.

5 0
3 years ago
Read 2 more answers
What is the median of 60 57 53 78 44 51 please help and thank u
maksim [4K]
To find the median cancel out numbers on both sides, until one is left in the middle and if there are two in the middle add them up and divide by two. 

So in this case the median is 
53+78
131 / 2
65.5
8 0
3 years ago
Read 2 more answers
Solve this equation. 4h + 6 =30
Vitek1552 [10]
First you subtract 6 from both sides to get:
      4h=24
Then divide by 4:
      h=6
With these problems, use the steps of either
PEDMAS, or <em></em>Please Excuse My Dear Aunt Sally.

the P stands for Parenthesis, the E for exponents, the M for multiplication, the D for division, the A for addition, and the S for subtraction


6 0
3 years ago
Read 2 more answers
What is typically used to quantitatively compare the effectiveness of layouts? A. trial and error B. load-distance model C. expo
Andre45 [30]

Answer:

B. load-distance model

Step-by-step explanation:

A. trial and error

Trial and error is "a fundamental method of problem solving. It is characterised by repeated, varied attempts which are continued until success". But this method is not the best in order to compare effectiveness of layouts

B. load-distance model

The load-distance method is a "mathematical model used to evaluate locations based on proximity factors. The objective is to select a location that minimizes the total weighted loads moving into and out of the facility. The distance between two points is expressed by assigning the points to grid coordinates on a map". And that's the correct option since we are trying to measure the effectiveness of layouts quantitatively.

C. exponential smoothing

This is "a rule of thumb technique for smoothing time series data using the exponential window function". Wheighting observations using the exponential function. But this is a techinique used to smooth s time series not to compare effectiveness of layouts.

D.process control charts

The Control Chart is a "graph used to study how a process changes over time with data plotted in time order". But we don't want to see how the process changes the objective is quantitatively compare the effectiveness of layouts, and this one is not the best option for this.

E. mean absolute deviation (MAD)

The median absolute deviation(MAD) is "a robust measure of how spread out a set of data is. The variance and standard deviation are also measures of spread, but they are more affected by extremely high or extremely low values and non normality". But again is just a measure of spread and not allow to compare effectiveness of layouts.

8 0
3 years ago
A phone manufacturer wants to compete in the touch screen phone market. He understands that the lead product has a battery life
alisha [4.7K]

Answer:

a)

The null hypothesis is H_0: \mu \leq 10

The alternative hypothesis is H_1: \mu > 10

b-1) The value of the test statistic is t = 1.86.

b-2) The p-value is of 0.0348.

Step-by-step explanation:

Question a:

Test if the battery life is more than twice of 5 hours:

Twice of 5 hours = 5*2 = 10 hours.

At the null hypothesis, we test if the battery life is of 10 hours or less, than is:

H_0: \mu \leq 10

At the alternative hypothesis, we test if the battery life is of more than 10 hours, that is:

H_1: \mu > 10

b-1. Calculate the value of the test statistic.

The test statistic is:

We have the standard deviation for the sample, so the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

10 is tested at the null hypothesis:

This means that \mu = 10

In order to test the claim, a researcher samples 45 units of the new phone and finds that the sample battery life averages 10.5 hours with a sample standard deviation of 1.8 hours.

This means that n = 45, X = 10.5, s = 1.8

Then

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.5 - 10}{\frac{1.8}{\sqrt{45}}}

t = 1.86

The value of the test statistic is t = 1.86.

b-2. Find the p-value.

Testing if the mean is more than a value, so a right-tailed test.

Sample of 45, so 45 - 1 = 44 degrees of freedom.

Test statistic t = 1.86.

Using a t-distribution calculator, the p-value is of 0.0348.

5 0
3 years ago
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