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tino4ka555 [31]
2 years ago
8

I need help putting correct answers in the yellow boxes.

Mathematics
1 answer:
olasank [31]2 years ago
7 0

Answer:

<u>-5 ± √5² - 4 · 1 · 4</u>

         2 · 1

Step-by-step explanation:

ax²+bx+c=0 (quadratic equation)

x=<u> -b ± √b² - 4ac</u>

           2a

a= 1

b= 5

c= 4

-<u>5 ± √5² - 4 · 1 · 4</u>

            2 · 1

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Can someone please help me out?
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explanation:

Isolate S on the left side by adding 1.9x to both sides. this gives you S = 4.8 + 1.9x. Plug in 22 for x because 2020 is 22 years from 1998.

4.8 + 1.9(22) = 46.6

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3 years ago
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Lines s and t are perpendicular. If the slope of line s is -5, what is the slope of line ?
stiks02 [169]

Answer:

B: 1/5

Step-by-step explanation:

If the lines are perpendicular, they have negative reciprocal slopes

s has a slope of -5

t must have a slope of - (1/ -5)

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3 years ago
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A metal hollow bar whose cross section and dimension are shown below weighs 8x10^3 kg/m^3 and measure 2m in length ..determine t
devlian [24]
1) We calculate the volume of a metal bar (without the hole).

volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
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Volume=(0.935 m²)(2 m)=1.871 m³

2) we calculate the volume of the parallelepiped

Volume of a parallelepiped= area of the section  x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³

3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar -  volume of a parallelepiped

Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³

4) we calculate the mass of the metal bar

density=mass/ volume  ⇒ mass=density *volume

Data:
density=8.10³ kg/m³
volume=1.551 m³

mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg

answer: The mas of the metal bar is 12.408x10³ kg  or   12408 kg  


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0.79 is more than half, so rounds to 1.

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