1 1 1 2
2 -3 1 -11 -2R1 + R2 → R2
-1 2 -1 8 R1 + R3 → R3
1 1 1 2
0 -5 -1 -15 R2 ⇔ R3
0 3 0 10
1 1 1 2
0 3 0 10 -R3
0 -5 -1 -15
1 1 1 2
0 3 0 10 1/3 R2
0 5 1 15
1 1 1 2 -R2 + R1
0 1 0 10/3 -5R2 + R3
0 5 1 15
1 0 1 -4/3
0 1 0 10/3 -R3 + R1
0 0 1 -5/3
1 0 0 1/3
0 1 0 10/3
0 0 1 -5/3
Therefore, x = 1/3, y = 10/3, z = -5/3
The time it took to complete 12 laps.
The independent, however, would be the car's speed or something like that.
Where are the variables for the equation?
Answer:
222 = score in 2nd game
Step-by-step explanation:
Let x = score in 1st game
3/4(x) + 30 = score in 2nd game
x + 3/4(x) + 30 = 478 Multiply thru by 4 to eliminate the fraction
4x + 3x + 120 = 1912
7x + 120 = 1912
7x = 1792
x = 256
3/4(x) + 30 = 3/4(256) + 30
= 192 + 30
222 = score in 2nd game
Check: 222 + 256 = 478
