C because first you would find the circumference of the circle which is pi times diameter, which is 18.84 but since it is a semi-circle you would divide by 2 which is 9.42. Then you do 3+3=6 + the length which is 6 so you get 12. 12+9.42=21.42 and if you round that to the nearest tenth it is 21.42.
Answer:
answer is 0.697 !
Step-by-step explanation:
Erica knits 39 on friday just add 21 and 18 then u get 39 hope i helped
Answer:
308[cos(45) + isin(45)]
Step-by-step explanation:
z1×z2:
Modulus: r1 × r2
= 7×44 = 308
Argument: theta1 + theta2
= -70 + 115 = 45
z1z2 = 308[cos(45) + isin(45)]
Or
z1z2 = 154sqrt(2) + (i)154sqrt(2)
sqrt: square root
You have not provided the diagram/coordinates for point Q, therefore, I cannot provide an exact answer.
However, I can help you with the concept.
When rotating a point 90° counter clock-wise, the following happens:
coordinates of the original point: (x,y)
coordinates of the image point: (-y,x)
Examples:
point (2,5) when rotated 90° counter clock-wise, the coordinates of the image would be (-5,2)
point (1,9) when rotated 90° counter clock-wise, the coordinates of the image would be (-9,1)
point (7,4) when rotated 90° counter clock-wise, the coordinates of the image would be (-4,7)
Therefore, for the given point Q, all you have to do to get the coordinates of the image is apply the transformation:
(x,y) .............> are changed into.............> (-y,x)
Hope this helps :)