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Svetlanka [38]
2 years ago
11

Tom drove to visit a museum in Chicago. He traveled at a constant rate of 50 miles per hour for 2 hours. Then he traveled at a c

onstant rate of 65 miles per hour for 1 hour. What is the total distance Tom traveled to the museum?
O:75
O:90
O:165
O:255
Mathematics
2 answers:
Dmitry [639]2 years ago
5 0

Answer:

165

Step-by-step explanation:

First, we multiply 50 and 2 to find out how much they traveled first, which is 100. And then, multiply 65 and 1 to get 65 for the second part. Add then, to get 165. Hope this helps!

zaharov [31]2 years ago
3 0

Answer:

The answer is 165 miles.

<em>This is how I solved it:</em>

<em>First I made a chart like the one in the picture</em>

<em>Then I inserted the </em><em>Rate </em><em>for each part of the trip. The rate for Part One is 50 miles per hour, and the rate for Part Two is 65 miles per hour.</em>

<em>Next, I would insert the</em><em> Time</em><em> for each part of the trip. The time for Part One is 2 hours, and the time for Part Two is 1 hour.</em>

<em>Because we now have the values for r and t for each part of the trip, we need to calculate the distance for each part by using the distance formula, d=r </em><u>x</u> <em>t, and multiplying the rate and the time.</em>

<em>For Part One, multiply 50 miles per hour x 2 hours; this equals 100 miles. For Part Two, multiply 65 miles per hour times 1 hour; this equals 65 miles.</em>

<u><em>So, Tom traveled 165 miles to the museum.</em></u>

<u><em>Hope this isn't confusing XD</em></u>

<u><em>FYI the attachment is just an example from another question so the answers are not the same</em></u>

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Answer:

Weight of EACH square = 0.2 pounds

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Step-by-step explanation:

Given that:

Weight of bag = 2 lb

Percentage of oat in mix = 18%

% of the mix is oats. (a) Use the 10 by 10 grid to represent 2 lb of trail mix. Determine how much weight each square represents and label all the squares. Then, shade in 18% of the grid. (b) What is the weight of the oats in the trail mix? Show your work and label your answer. Answer:

If trail mix is represented by 10 by 10 square grid ;

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3 years ago
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Find the mass of the solid paraboloid Dequals=​{(r,thetaθ​,z): 0less than or equals≤zless than or equals≤8181minus−r2​, 0less th
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Answer:

M = 5742π  

Step-by-step explanation:

Given:-

- Find the mass of a solid with the density ( ρ ):

                             ρ ( r, θ , z ) = 1 + z / 81

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Solution:-

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                           M = \int \int \int {p ( r ,theta, z)} \, dV\\\\

- We can write the above expression in cylindrical coordinates:

                           M = \int\limits\int\limits_r\int\limits_z {r*p(r,theta,z)} \, dz.dr.dtheta \\\\M = \int\limits\int\limits_r\int\limits_z {r*[ 1 + \frac{z}{81}] } \, dz.dr.dtheta\\\\

- Perform integration:

                           M = \int\limits\int\limits_r{r*[ z + \frac{z^2}{162}] } \,|_0^8^1^-^r^2 dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{(81-r^2)^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{6561 -162r + r^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + 40.5 -r +\frac{r^2}{162} ] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{[ 121.5r-r^2 -\frac{161r^3}{162} ] } \, dr.dtheta\\\\

                           M = 2*\int\limits_0^\pi {[ 121.5r^2-r^3 -\frac{161r^4}{162} ] } |_0^6 \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 121.5(6)^2-(6)^3 -\frac{161(6)^4}{162} ] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 4375-216 -1288] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 2871] }  \, dtheta\\\\M = 5742\pi  kg              

- The mass evaluated is M = 5742π                      

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Step-by-step explanation:

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