If A=38x-x^2 then
dA/dx=38-2x
d2A/dx2=-2
Since the acceleration, d2A/dx2 is a constant negative, when velocity, dA/dx=0, it will be an absolute maximum for A(x)
dA/dx=0 only when 38=2x, x=19
A(19)=38(19)-19^2
A(19)=722-361
A(19)=361 ft^2
So the maximum possible area is 361 ft^2
(This will always be true as the maximum possible area enclosed by a given amount of material will always be a perfect square...)
we are given
Firstly, we will factor out 16
we can write it as
we can replace it as
now, we can use property of log
we get
.............Answer
Answer:
Yeah its 7 because when you add 3+2=5, and x is 2, its 7
F. An experiment because they are conducting a study and experimenting with a sample different from what is known
