In parallelogram DEFG, DH = x + 3, HF = 3y, GH = 4x – 5, and HE = 2y + 3. Find the values of x and y.
2 answers:
Here, DH = HF
x+3 = 3y
x = 3y-3 ----(I)
GH = HE
4x-5 = 2y+3
4x = 2y+8
Substitute value of x,
4(3y-3) = 2y+8
12y-12 = 2y+8
12y-2y = 12+8
10y = 20
y = 2
Now, substitute it in equation 1,
x = 3(2)-3
x = 6-3 = 3
So, your final answer is x=3 & y=2
Ince DH=HF you set x+3=3y <span>GH=HE so 4x-5=2y+3 </span> <span>This gives you a system and I solved by substitution so I got x alone in the first equation-> x=3y-3 </span> <span>then I plugged this x into the second equation so </span> <span>4(3y-3)-5=2y+3 </span> <span>12y-12-5=2y+3 </span> <span>12y-17=2y+3 </span> <span>10y=20 </span> <span>y=2 </span> <span>plug y into the first equation to find x </span> <span>x=3(2)-3 </span> <span>x=6-3 </span> <span>x=3 </span> <span>therefore x=3, y=2</span>
You might be interested in
Digit in ones place- 6 Digit in tenths place- 5
Answer:like terms: 5x + -9x = -4x 6 + -2x = -12 + -4x Solving 6 + -2x = -12 + -4x Solving for variable 'x'.
Step-by-step explanation:
6 - 2x = 5x - 9x + 18 - 12 6 - 2x = -4x + 6 -2x = -4x 4x - 2x = 0 2x = 0 x = 0 / 2 x = 0.
change it to 269 then add 15
I think that the answe my be b
3^2 + (8 - 2) x 4 - 6/3
=9 + 24 - 2
=33 - 2
=31