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Monica [59]
3 years ago
11

In parallelogram DEFG, DH = x + 3, HF = 3y, GH = 4x – 5, and HE = 2y + 3. Find the values of x and y.

Mathematics
2 answers:
marissa [1.9K]3 years ago
3 0

Here, DH = HF 

x+3 = 3y

x = 3y-3   ----(I)

GH = HE

4x-5 = 2y+3

4x = 2y+8

Substitute value of x,

4(3y-3) = 2y+8

12y-12 = 2y+8

12y-2y = 12+8

10y = 20

y = 2

Now, substitute it in equation 1,

x = 3(2)-3

x = 6-3 = 3

So, your final answer is      x=3  & y=2



Likurg_2 [28]3 years ago
3 0
Ince DH=HF you set x+3=3y 
<span>GH=HE so 4x-5=2y+3 </span>

<span>This gives you a system and I solved by substitution so I got x alone in the first equation-> x=3y-3 </span>
<span>then I plugged this x into the second equation so </span>

<span>4(3y-3)-5=2y+3 </span>
<span>12y-12-5=2y+3 </span>
<span>12y-17=2y+3 </span>
<span>10y=20 </span>
<span>y=2 </span>

<span>plug y into the first equation to find x </span>
<span>x=3(2)-3 </span>
<span>x=6-3 </span>
<span>x=3 </span>

<span>therefore x=3, y=2</span>
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