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Artyom0805 [142]
2 years ago
6

A bag of candy has a mass of 80 g. A chocolate bar has a mass of 110 g. What is the total mass of the bag of candy and the choco

late bar? (10 points) [help if you want points!]
Mathematics
1 answer:
atroni [7]2 years ago
3 0

total mass = mass of a bag of candy + mass of a chocolate bar

total mass = 80g +110g = 190g

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Given a right triangle with a hypotenuse of 6 cm and a leg of 4cm, what is the measure of the other leg of the triangle rounded
slega [8]

Answer:

4.5 cm=L2

Step-by-step explanation:

This problem can be solved using the pythagorian theoreme:

H=\sqrt{L1^{2}+L2^{2}  }

Where:

H=6 cm

L1=4 cm

L2=?

We isolate our incognita an we get:

\sqrt{H^{2}-L1^{2}} =L2

We supplant with the given data:

\sqrt{(6cm)^{2}-(4cm)^{2}} =L2

\sqrt{36cm^{2}-16cm^{2}} =L2

\sqrt{36cm^{2}-16cm^{2}} =L2

\sqrt{20cm^{2}} =L2

4.5 cm=L2

5 0
3 years ago
The Area of a rectangle is 27cm² and the length is 9cm,find the Breadth?
telo118 [61]

Answer:3


Step-by-step explanation:


6 0
3 years ago
Below are the results of tossing a number cube 7times. Find the experimental probability of tossing an even number. 6 4 3 2 5 3
Daniel [21]
3/7 or 3:7 because you tossed the dice 7 times and got an even number 3 of those times.
7 0
3 years ago
Read 2 more answers
Find the volume of the composite figure​
AURORKA [14]

39in³ is a required volume.

Solution given:

for upper one

length[l]=8in

breadth[b] =3in

height[h]=1in

now

volume [V1]=l×b×h=8×3×1=24in³

again for lower one:

length[l]=6-1=5in

breadth[b] =3in

height[h]=1in

volume [V2]=l×b×h=5×3×1=15in³

Again

total volume =V1+V2=24in³+15in³=39in³

6 0
3 years ago
A game of chance involves spinning a wheel with 4 number on it. The wheel is designed so that the result of each spin Xhas the f
Kipish [7]

Distribution table :

X : ___ 1 _____ 2 _____ 3 ______ 4

P(x) __0.50 __0.25 __ 0.15 ____ 0.10

Answer:

1.85 ; 1.014 ;` 0.55 ; 3.042

Step-by-step explanation:

Probability distribution :

X : ___ 1 _____ 2 _____ 3 ______ 4

P(x) __0.50 __0.25 __ 0.15 ____ 0.10

The mean: E(x) = Σ(X * p(x))

(1*0.5) + (2*0.25) + (3*0.15) + (4 *0.10)

= 1.85

Standard deviation = sqrt(Var(x))

Var(x) = Σ(x²*p(x)) - E(x)²

Var(x) = ((1^2*0.5) + (2^2*0.25) + (3^2*0.15) + (4^2 *0.10)) - 1.85^2

= 4.45 - 3.4225

= 1.0275

Standard deviation = sqrt(1.0275)

Standard deviation = 1.0136567

Standard deviation(X) = 1.014

3.)

Cost of spin = $5

Amount, y to be received = 3 times the number that appears

y = 3x - cost of playing

y = 3x - 5

E(y) = E(3x - 5)

E(y) = E(3x) - 5

Recall :E(x) = 1.85

E(y) = 3(1.85) - 5

E(y) = 0.55

Standard deviation :Sd(y) =

Sd(3x - 5)

3(1.014)

= 3.042

5 0
3 years ago
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