26 for ad and bd 13 I believe
Answer:
5.4 feet
Step-by-step explanation:
Let the reference line
represents the sea level without any elevation.
At 1 P.M. the ocean surface was at an elevation of 2.2 feet along the line
in the figure and the surf shop was 8.2 feet above of this elevated ocean's surface along the line
in the figure.
Similarly, at 7 P.M. the ocean surface was at an elevation of -2.4 feet along the line
in the figure and the deck in the restaurant was 8.2 feet above of this elevated ocean's surface along the line
in the figure.
From the figure, the distance between the deck and the ocean's surface at 1 P.M.= The distance between the lines
and
.
![d= 10- (d_1+d_2)](https://tex.z-dn.net/?f=d%3D%2010-%20%28d_1%2Bd_2%29)
![=10-(2.2+2.4)](https://tex.z-dn.net/?f=%3D10-%282.2%2B2.4%29)
=5.4 feet
Hence, the distance between the deck and the ocean's surface at 1 P.M. is 5.4 feet.
Answer:
Step-by-step explanation:
Answer:
15+25d=t
Step-by-step explanation:
the initial value is 15 it increases(+) by 25 to each kilometer(distance=d) of depth.
Step-by-step explanation:
Area of parallelogram = base×height
= 13×5
= 65m²