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SVETLANKA909090 [29]
3 years ago
9

I need help I don’t understand the problem#5

Mathematics
2 answers:
vampirchik [111]3 years ago
7 0
the answer is A) 176
aleksandrvk [35]3 years ago
3 0
A) 176 is your correct anwser
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8(2n - 5) = 3(6n - 2)
joja [24]

Answer:

n=-17

Step-by-step explanation:

8(2n-5)=3(6n-2)

1) Distributive property

16x-40=18x-6

16x−40=18x−6

2) Subtract 16x16x from both sides.

-40=18x-6-16x

−40=18x−6−16x

3) Simplify 18x-6-16x18x−6−16x to 2x-62x−6.

-40=2x-6

−40=2x−6

4) Add 66 to both sides.

-40+6=2x

−40+6=2x

5) Simplify -40+6−40+6 to -34−34.

-34=2x

−34=2x

6) Divide both sides by 22.

-\frac{34}{2}=x

−

2

34

=x

7) Simplify \frac{34}{2}

2

34

to 17

−17=x

8) Switch sides.

x=−17

5 0
3 years ago
Find the value of x.
Ivahew [28]

Answer:

58

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Pattern A was created by using the rule "start at 2 and add 3." Pattern B was created by using the rule "start at 14 and subtrac
uysha [10]

Answer:

(2, 14), (5, 12), (8, 10), (11, 8), (14, 6)

Step-by-step explanation:

Lets do the math for Pattern A:

2 + 3 = 5

5 + 3 = 8

8 + 3 = 11

11 + 3 = 14

Lets do the math for Pattern B:

14 - 2 = 12

12 - 2 = 10

10 - 2 = 8

8 - 2 = 6

6 - 2 = 4

7 0
3 years ago
2 Mayra is a caterer and charges $75 per plate plus a
dimulka [17.4K]

Answer:

$11,280

Step-by-step explanation:

Plug in 150 as p into the equation to solve for the cost, C:

C = 30 + 75p

C = 30 + 75(150)

C = 30 + 11,250

C = 11,280

= $11,280

5 0
3 years ago
If Jesse wants to buy a $75,000 10-year term life insurance policy, and the annual premium rate (per $1000 of face value) for hi
Komok [63]

Step-by-step explanation:

Since it is given that it costs $2.34 for every $1000 face value, and it was given that he wanted to buy a $75000 plan, multiplying $2.34 by 75 (75000 includes 75 $1000 face value), it should yield us the annual premium.  

2.34 * 75 = $175.50

We don't need to multiply it by 10 years as only the annual premium is being solved for.

7 0
3 years ago
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