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1 year ago

Can some one answer this question please show work

Mathematics

1 answer:

Lera25 [3.4K]1 year ago

4 0

When you reflect across the Y axis, the Y value remains the same and the x value becomes opposite.

Answer: (5,-3)

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Evaluate -6(x-2y) when x= -3 and y= -5<br> a. -42<br> b. 80<br> c. -80<br> d. -16

Vinil7 [7]

Simply substitute x for -3 and y for -5, creating the equation shown below:

-6 (-3 - 2(-5) )
Now that you have your values set up, now you can do the math by starting off with Multiplying -2 by -5, which will get you 10.

Now that you have the parenthesis simplified in the parenthesis, you can use the distributive property by multiplying all the numbers with -6, like so:
-6(-3+10)= 18 - 60, which simplifies to -42, in which (A) is your answer.

5 0

2 years ago

Read 2 more answers

Which expression is equivalent to

lapo4ka [179]

The last one
2j^2/3k^4

6 0

2 years ago

Build a fence around his rectangular garden. The length is 30 feet. The width is 6 yards. How many feet of fencing is needed

nadya68 [22]

The field that is being fenced in has two 30 foot sides and 2 18 foot sides. The reason they are 18 is because there are 3 feet in a yard. You would then add all 4 sides together, equaling your perimeter.

The final answer is 96 sq feet.

4 0

2 years ago

WILL MARK BRAINLIEST!

Artist 52 [7]

Answer:

Following are the responses to the given points:

Step-by-step explanation:

Dilation implies the triangle $\Delta XYZ$ stretched through the factor "2".

$m\angle Y = m\angle C = 90^{\circ} \leftarrow given \\\\$

right triangles:

$\Delta XYZ and \Delta ACB \\\\\angle X \cong \angle A \leftarrow given\\\\$

complementary angles:

$\angle X \ and\ \angle Z$

$m\angle Z = 90^{\circ} - m\angle X \\\\$

complementary angles:

$\angle A \ and\ \angle B$

$m\angle B = 90^{\circ} - m\angle A \\\\\therefore \\\\ \angle Z \cong \angle B \\\\\Delta XYZ \sim \Delta ACB \\\\$

Same triangles: proportional side are corresponding, congruence angles are respective.

$\sin \angle X = \frac{5}{5.59} \leftarrow given \\\\\sin\angle X = \frac{YZ}{XY} \\\\YZ = 5 (units) \rightarrow leg in \Delta XYZ \\\\XZ = 5.59 (units) \rightarrow hypotenuse \ in\ \Delta XYZ\\\\$

Calculating the length of leg XY:

$XY = \sqrt{((5.59)^2 - 52)} \cong 2.4996 (units)\\\\\frac{CB}{YZ} = 2 \leftarrow given \\\\CD = 2YZ = 2 \times 5 = 10 \ (units)\\\\\frac{AC}{XY} = 2 \leftarrow \ given\\\\AC = 2XY \cong 2 \times 2.4996 \cong 4.999\ (units)\\\\$

3 0

2 years ago

Rewrite in simplest terms: 4 x − 5 ( x + 3 )

rusak2 [61]

Answer:

Step-by-step explanation:

4x - 5(x + 3) Remove the brackets. Watch the - sign and -5*3

4x - 5x - 15 Combine the xs

-x - 15

4 0

2 years ago