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3 years ago

Use elimination to solve only number 7

Mathematics

1 answer:

anzhelika [568]3 years ago

7 0

So the vs eliminate each other which leaves the ws and the 1,7. Then you add the 2 ws to get 2w and then add the numbers to get 2w=8, then divide 8 by 2 and you get w=4

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A right triangle has leg measures of 8 and 15 inches. What is the area and perimeter of the triangle?

rewona [7]

Hello!

<h3><em><u>Answer</u></em></h3>

The area of the right triangle is 30 $in^{2}$ . The perimeter is 40 in.

<h3><em><u>Explanation</u></em></h3>

First, we must find the measure of the hypotenuse of the triangle by using the Pythagorean Theorem.

$a^{2}$ + $b^{2} = c^{2}$

$8^{2} + 15^{2} = c^{2}$

64 + 225 = $c^{2}$

√289 = $c^{2}$

17 = $c$

Now that we have all the side lengths, we can use the formulas to find the area and perimeter.

A = $\frac{bh}{2}$

A = (15 × 8) ÷ 2

A = 30

<h3>PERIMETER:</h3>

P = a + b + c

P = 8 + 15 + 17

P = 40

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3 years ago

Ethan Doran is a physical therapist. His biweekly salary is $3,985. What is his annual salary? (Hint: You need to know how many

NNADVOKAT [17]

103,610.00 you welcome.

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3 years ago

Every week at the Cougar Scouts meeting, Diane is in charge of the craft activity. This week, she decides to make pinecone bird

liraira [26]

Answer:

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3 years ago

What are the first 5 multiples of 150

anzhelika [568]

Answer:

150, 300, 450, 600, 750

Step-by-step explanation:

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3 years ago

You are designing a rectangular garden. the garden will be enclosed by fencing on three sides and by a house on the fourth side.

RUDIKE [14]

Suppose the dimensions of the rectangle is x by y and let the side enclosed by a house be one of the sides measuring x, then the sides that is to be enclosed are two sides measuring y and one side measuring x.

Thus, the length of fencing needed is given by

P = x + 2y

The area of the rectangle is given by xy,

i.e.

$xy = 288 \\ \\ \\ \\ \Rightarrow y= \frac{288}{x}$

Substituting for y into the equation for the length of fencing needed, we have

$P=x+2\left( \frac{288}{x} \right)=x+ \frac{576}{x}$

For the amount of fencing to be minimum, then

$\frac{dP}{dx} =0 \\ \\ \Rightarrow1- \frac{576}{x^2} =0 \\ \\ \Rightarrow \frac{576}{x^2} =1 \\ \\ \Rightarrow x^2=576 \\ \\ \Rightarrow x=\sqrt{576}=24$

Now, recall that

$y= \frac{288}{x} = \frac{288}{24} =12$

Thus, the length of fencing needed is given by

P = x + 2y = 24 + 2(12) = 24 + 24 = 48.

Therefore, 48 feets of fencing is needed to enclose the garden.

8 0

3 years ago