Segment PT || segment QS, Given
segment PT ≅ segment QS,
∠T ≅ ∠S
Angle TPQ = Angle SQR PR is a transversal cutting parallel segments SQ and TP
So....it makes corresponding angles TPQ and SQR equal
ΔPQT ≅ ΔQRS ASA congruency
Step-by-step explanation:
check the image that is your answer
For this equation you would need to combine like terms
Step 1: -2+1= -1
Step 2: -4i+6i= 2i
so your answer to this question would be -1+2i
Answer:
x = 12
Step-by-step explanation:
Angle GHK is half of 120, so is 60. Then ...
3x +24 = 60
3x = 36 . . . . . subtract 24
x = 12 . . . . . . . divide by 3