Ask question

Ask question

All categories

3 years ago

14

Mr. Jones spends $156 to attend a college football game. Twenty percent of his cost was for a pass for parking. He spend the rem

ainder of his money on two tickets for the game. What is the price for each ticket?

1 answer:

likoan [24]3 years ago

8 0

62.40 for each ticket.

156 x 20 = 3120.

3120 / 100 = 31.2

156 - 31.2 = 124.8

124.8 / 2 = 62.40

You might be interested in

What is the interquartile range of the data set?

AveGali [126]

There is no data provided but if your asking what an interquartile range is ?? It’s a measure of variability based on dividing a data set into quartile a

6 0

2 years ago

To join a local square dancing group, Jan has to pay a $100 sign-up fee plus $25 per month. Write an equation for the cost (y) b

klasskru [66]

Answer:

y = $100 + $25x

Step-by-step explanation:

y is the total cost

x is the number of months

The sign up fee is $100.

Each month would cost an additional $25 per month.

The total cost then would be the sign up fee plus the $25 for each month. Since we do not know the number of months, we will assign x.

So the equation would be:

y = $100 + $25x

3 0

3 years ago

What is the union of the set (1, 4, 6, 8 1/2,10) and (1, 3, 11/2, 6, 10 1/2)

makkiz [27]

Answer:

$(1, 4, 6, 8, \frac{1}{2}, 10, 3, \frac{11}{2})$

Step-by-step explanation:

We need to find union of given sets $(1, 4, 6, \frac{1}{2}, 10)$ and $(1, 3, \frac{11}{2}, 10, \frac{1}{2})$

We know by definition that union of two given sets say A and B is set C with all the unique and common values given in set A and B.

∴ $(1, 4, 6, \frac{1}{2}, 10)$ ∪ $(1, 3, \frac{11}{2}, 10, \frac{1}{2})$ = $(1, 4, 6, 8, \frac{1}{2}, 10, 3, \frac{11}{2})$

4 0

3 years ago

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

7 0

2 years ago

HELP PLZ Which decimal is equivalent to ? A. 4.03 B. 4.12 C. 4.25 D. 4.30

MAVERICK [17]

The answer is C. 4.25

4 0

2 years ago