The answer for this question is 1468
Answer:
28°
Step-by-step explanation:
You're given that line DE and line FG are parallel and KL and FG are perpendicular. Then you can find out angle ∠BAC by using the vertical angles property: ∠BAC=62°. Then since KL and FG are perpendicular ∠ABC = 90°. So you find the angle ∠BCA by finding the sum of interior angles: 62+90+∠BCA=180, therefore ∠BCA is 28°. Finally, ∠x or ∠JCG = 28 because ∠JCG and ∠BCA are vertical angles and congruent.
Answer:
2x - 10
Step-by-step explanation:
2(x - 5)
distribute
2*x - 2*5
2x - 2*5
2x - 10
Prob 70-74 depending on your school grading system
<span>3x – 15y = 60
y-intercept x = 0</span>
3(0)– 15y = 60
-15y = 60
y = -4
x-intercept y = 0
3x– 15(0) = 60
3x = 60
x =20
answer :
<span>C. x-intercept: 20; y-intercept: –4</span>
