Answer:
5.415m and 2.585m long
Step-by-step explanation:
For a right triangle
hyp^2 = opp^2 + adj^2 (Pythagoras theorem)
Given
hypotenuse = 6m
height(opposite) = h meters
Adjacent = (8-h)m
Substitute into the expression above;
6² = h²+(8-h)²
36 = h²+64-16h+h²
36 = 2h²-16h+64
2h²-16h+64-36 = 0
2h²-16h+28= 0
Divide through by 2
h²-8h+14 = 0
Using the general formula
h = 8±√8²-4(14)/2
h = 8±√64-56/2
h = 8±√8/2
h = 8±2.83/2
h = 8+2.83/2 and 8-2.83/2
h = 10.83/2 and 5.17/2
h = 5.415 and 2.585
hence the length of the height of the right triangle are 5.415m and 2.585m long
add 0+1+2+3+4 = 10
divide 10÷5 = 2
add 15+8+3+3+1 = 30
divide 30÷5 = 6
the ratio is 2:6 which simplifies to 1:3 by the means of lates per student. In other words there is one late per 3 students.
Answer:
102°
Step-by-step explanation:
This is an isosceles triangle
x = 180 - 39 - 39
x = 102°
Hi again!
I think I already answered this question - right ?
Ok whatever - the answer and the steps are still in my head~
x^3 - 4x² + 2x + 10 = x² - 5x - 3
Again, same thing
x^3 - 4x² + 2x + 10 -x² + 5x + 3 = 0
Now factorize
(x + 1)(x² - 6x + 13) = 0
Set factor equal to 0
x + 1 = 0 or x² - 6x + 13 = 0
x = -1
The correct option is : B
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Answer: then he had $70.80
Step-by-step explanation:
