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galben [10]
2 years ago
8

A bag of fruit contains 3 apples, 2 oranges, 1 banana, and 4 pears, Gerald will randomly select two pieces of fruit

Mathematics
1 answer:
Leto [7]2 years ago
5 0

Answer:

2/45

Step-by-step explanation:

The probability that a banana is picked for the first one is:

1/10

because there are 10 fruits and one of them is a banana,

Then, the second piece has to be a pear.

For this we have already picked one fruit out of the bag, which leaves 9 fruits in the bag.

There are 4 pears so the probability of picking a pear second is

4/9

To find the probability of a banana and then a pear, you want to multiply these values together

So:

1/10 x 4/9 = 4/90 = 2/45

So the probability is 2/45

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iren [92.7K]

Step-by-step explanation:

a) 24.7×52.3=1291.81

On rounding off to 3 significant digits we get

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\sqrt{ {42}^{2} -  {28}^{2}  }

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