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galben [10]
2 years ago
8

A bag of fruit contains 3 apples, 2 oranges, 1 banana, and 4 pears, Gerald will randomly select two pieces of fruit

Mathematics
1 answer:
Leto [7]2 years ago
5 0

Answer:

2/45

Step-by-step explanation:

The probability that a banana is picked for the first one is:

1/10

because there are 10 fruits and one of them is a banana,

Then, the second piece has to be a pear.

For this we have already picked one fruit out of the bag, which leaves 9 fruits in the bag.

There are 4 pears so the probability of picking a pear second is

4/9

To find the probability of a banana and then a pear, you want to multiply these values together

So:

1/10 x 4/9 = 4/90 = 2/45

So the probability is 2/45

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Answer: Assuming the function is g(x)=\frac{2x+1}{x-3}:

The x-intercept is (\frac{-1}{2},0).

The y-intercept is (0,\frac{-1}{3}).

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The vertical asymptote is x=3.

Step-by-step explanation:

I'm going to assume the function is: g(x)=\frac{2x+1}{x-3} and not g(x)=2x+\frac{1}{x}-3.

So we are looking at g(x)=\frac{2x+1}{x-3}.

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

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A fraction is only 0 when it's numerator is 0.  You are really just solving:

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The y-intercept is when x is 0.

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g(0)=\frac{2(0)+1}{0-3}

y=\frac{2(0)+1}{0-3}  

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y=-\frac{1}{3}.

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The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

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x=3

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So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is y=\frac{2}{1}.  After simplifying you could just say the horizontal asymptote is y=2.

Or!

I could do some division to make it more clear.  The way I'm going to do this certain division is rewriting the top in terms of (x-3).

y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}

y=2+\frac{7}{x-3}

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

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