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algol [13]
3 years ago
14

Idk this and it’s due tomorrow but I don’t have the slightest clue on how to do it

Mathematics
1 answer:
vovikov84 [41]3 years ago
4 0
Well if her speed is 55 miles per hour
1 hour= 55 miles
? hour= 192 miles
You can divide by 55 and get
3.5 ( I rounded the number)
Hope this helps?
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What are the steps to solve -2n-(9-10n) ?
larisa86 [58]
<span> (9+10n)(9-10n) </span>Final result : (10n + 9) • (9 - 10n)

Step by step solution :<span> Step  1  :</span>Final result :<span> (10n + 9) • (9 - 10n) </span>
8 0
3 years ago
The semicircle shown at left has center X and diameter WZ. The radius XY of the semicircle has length 2. The chord YZ has length
GaryK [48]

Answer:

4π/3 square units

Step-by-step explanation:

Triangle XYZ is equilateral,

The central angle of the sector is 120°, or 2π/3 radians.

The area of a sector of central angle β is given by

.. A = (1/2)r^2*β . . . . . . β in radians

.. A = (1/2)*2^2*(2π/3) = 4π/3 square units

5 0
3 years ago
What is the measures of ∠x
Sloan [31]

Answer:

x = 64

Step-by-step explanation:

∠ HIA and ∠ LJK are corresponding angles and congruent, thus

∠ HIA = 60°

The sum of the 3 angles in Δ HIA = 180° , thus

x = 180 - (60 + 56) = 180 - 116 = 64

7 0
3 years ago
If g(x, y) = x2 + y2 − 6x, find the gradient vector ∇g(2, 6) and use it to find the tangent line to the level curve g(x, y) = 28
Alekssandra [29.7K]

Answer:

The gradient of vector

   ∇g = i⁻(2 x -6 ) +  j⁻ (2y)

The gradient of vector at the point (2 ,6) is

( ∇g)₍₂,₆) =    (-2)  i⁻ +   (12) j⁻

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given  g (x, y) = x² +y² -6x ...(i)

The gradient of vector

     ∇g =( i⁻ δ/δx + j⁻ δ/δy+ k⁻δ/δZ)g

          = ( i⁻ δg/δx + j⁻ δg/δy+ k⁻δg/δZ)  .....(ii)

Differentiating equation (i) partially with respective to 'x' , treated 'y' as constant.

δg/δx = 2x - 6

Differentiating equation (i) partially with respective to 'x' , treated 'y' as constant.

δg/δy = 2y

<u><em>Step(ii)</em></u>:-

The gradient of vector

   ∇g = i⁻(2 x -6 ) +  j⁻ (2y)

At the point ( 2,6)

( ∇g)₍₂,₆) = i⁻(2 (2) -6 ) +  j⁻ (2(6))

( ∇g)₍₂,₆) =    i⁻(-2) +  j⁻ (12)

7 0
3 years ago
Write the factors of 14 Circle the prime numbers
Ludmilka [50]
1, 2, 7, and 14. 2 and 7 are prime numbers.
8 0
3 years ago
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