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butalik [34]
2 years ago
9

Please help I will give brainliest

Mathematics
1 answer:
Hunter-Best [27]2 years ago
7 0

Answer:

D

Step-by-step explanation:

IM RLY SORRY IF THIS IS WRONG IM DOING THIS FORM MEMORY

so I'm pretty sure u the arch equals twice the angle

so pi/2*2 = pi so D

hope it helppsss

trying not to dieT-T

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524+920 Enter your answer either as an integer or as a fraction in simplest form
oee [108]

Answer:

1444

Step-by-step explanation:

524 + 920 = 1444

5 0
3 years ago
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An art club sells 42 large candles and 56 small candle price of large candle is $10 the cost is $x a small candles cost $5 and c
balandron [24]

Answer:

Profit = $(700 - 42x - 56y)

Step-by-step explanation:

For large candles, the selling price is $10 and its making cost is $x.

So, by selling a large candle the profit is $(10 - x)

Again for small candles, the selling price is $5 and its making cost is $y.

So, by selling a small candle the profit is $(5 - y)

Therefore, in a sell of 42 large candles and 56 small candles the total profit will be, P = 42 (10 - x) + 56 (5 - y)

⇒ P = 420 - 42x + 280 - 56y {Applying distributive property}

⇒ P = $(700 - 42x - 56y) (Answer)

4 0
3 years ago
(-8) x 10 x 9 is equal to
Sergio [31]

Answer:

-720

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
For the function f(x)
WITCHER [35]

Given:

The function is

f(x)=\dfrac{8\sqrt[3]{x}-8}{9}

To find:

The inverse function f^{-1}(x).

Solution:

We have,

f(x)=\dfrac{8\sqrt[3]{x}-8}{9}

Step 1: Putting f(x)=y, we get

y=\dfrac{8\sqrt[3]{x}-8}{9}

Step 2: Interchange x and y.

x=\dfrac{8\sqrt[3]{y}-8}{9}

Step 3: Isolate variable y.

9x=8\sqrt[3]{y}-8

9x+8=8\sqrt[3]{y}

\dfrac{9x+8}{8}=\sqrt[3]{y}

Taking cube on both sides, we get

\left(\dfrac{9x+8}{8}\right)^3=y

y=\left(\dfrac{9x+8}{8}\right)^3

Step 4: Putting y=f^{-1}(x), we get

f^{-1}(x)=\left(\dfrac{9x+8}{8}\right)^3

Therefore, the correct option is C.

4 0
2 years ago
ASAP help due today brainliest
umka2103 [35]
B i think.. the product kinda gives it off to me but i’m not sure
5 0
3 years ago
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