(x - a)^2 + (y - b)^2 = (y - d)^2
<span>x^2 - 2ax + a^2 + y^2 - 2by + b^2 = y^2 - 2dy + d^2 </span>
<span>Subtract y^2 from both sides... </span>
<span>x^2 - 2ax + a^2 - 2by + b^2 = -2dy + d^2 </span>
<span>Now I would just substitute in the the values (a = -4, b = 17/8, d = 15/8)... </span>
<span>x^2 - 2(-4)x + (-4)^2 - 2(17/8)y + (17/8)^2 = -2(15/8)y + (15/8)^2 </span>
<span>Simplify... </span>
<span>x^2 + 8x + 16 - (17/4)y + 289/64 = -(15/4)y + 225/64 </span>
<span>Add (17/4)y to both sides... </span>
<span>x^2 + 8x + 16 + 289/64 = (2/4)y + 225/64 </span>
<span>x^2 + 8x + 16 + 289/64 = (1/2)y + 225/64 </span>
<span>Subtract 225/64 from both sides... </span>
<span>x^2 + 8x + 16 + 1 = (1/2)y </span>
<span>x^2 + 8x + 17 = (1/2)y </span>
<span>Multiply both sides by 2... </span>
<span>2x^2 + 16x + 34 = y </span>
<span>...which is equal to equation D.</span>
Using the z-distribution, the 90% confidence interval for the difference of proportions is given by: (-0.0534, 0.0434).
<h3>What is the mean and the standard error for the distribution of differences?</h3>
For each sample, the mean and the standard error are given as follows:
.
.
For the distribution of differences, they are given by:
.
<h3>What is the confidence interval?</h3>
The interval is given by:
In this problem, we have a 90% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 1.645.
Hence the bounds of the interval are:
More can be learned about the z-distribution at brainly.com/question/25890103
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Whcih one you need to say your problem
Answer: x=2
Step-by-step explanation:
