Answer:
1) Event A = 2/3
Event B = 1/2
2) 1/2
Step-by-step explanation:
1)
Event A :
No. we need on dice = 4
Total numbers on dice = 6
Hence sample space of the event = 6
P( getting 4) = 4/6 = 2/3
Event B :
A coin has a head & a tail.
Hence sample space of the event = 2
But as we need tail only ,
P ( getting Tail ) = 1/2 [ if only tossed once ]
2)
Total numbers on a die = 6
Total no. of odd numbers on die = 3 (∵ 1 , 3 & 5 are odd )
Sample space of this event = 6
P (getting an odd number) = 3/6 = 1/2
Ab = (7x-6) → b = (7x-6)/a (1)
bc = (12-2x) → b = (12-2x)/c (2)
Since (1) = (2) → (7x-6)/a = (12-2x)/c OR a/c = (7x-6)/(12-2x) (3)
Multiply both numerators of (3) by the SQUARE of their respective denominators;
(a*c²)/c = (7x-6)(12-2x)²/(12-2x)
Now simplify:
ac = (7x-6)(12x-2x) or ac = -14x² + 96x - 72
Answer:
160 visitors.
Step-by-step explanation:
Given:
An average of 145 people visited a 4-day exhibition on the first 3 days, <u>means here average people visited in 3 days is given 145.</u>
Average = 145
Number of people, n = 3
Another 205 people visited the exhibition on the fourth day.
To find:
What is the average number of visitors per day ?
Solution:
<u>First of all we will find total number of people visited in 3 days:-</u>
As we know:


Multiplying both sides by 3

Thus, we found that total number of people visited in 3 days is 435 and as 205 people visited in fourth day, then total number of people increased to
435 + 205 = 640
Now, sum of total observations( total number of people ) = 640
And number of observation ( number of days ) = 4
Now, we will calculate average number of visitors visit per day :-


Thus, the average number of visitors per day is 160 visitors.
745/x=100/36
<span>(745/x)*x=(100/36)*x
</span><span>745=2.7777777777778*x
</span>(2.7777777777778) to get x
<span>745/2.7777777777778=x </span>
<span>268.2=x </span>
<span>x=268.2
</span>
answer <span>36% of 745=268.2</span>