What is 46+8-(4x15)+9

Mr. I does a job in x hours while Mr. L can do it in y hours. How much of the job could they do together if they were to work fo

dimulka [17.4K]

Answer: Work done by both of them in k hours is

$\frac{k(x+y)}{xy}$

Explanation:

Since we have given that

Number of hours Mr. I does a job = x hours

Number of hours Mr. L does a job = y hours

Work done by Mr. I is given by

$\frac{1}{x}$

Work done by Mr. L is given by

$\frac{1}{y}$

Work done if they do together is given by

$\frac{1}{x}+\frac{1}{y}\\\\=\frac{x+y}{xy}$

Work done if they work together for k hours is given by

$\frac{x+y}{xy}\times k\\\\=\frac{k(x+y)}{xy}$

Hence, work done by both of them in k hours is

$\frac{k(x+y)}{xy}$

3 0

3 years ago

an automobile has 20 inch diameter wheels if the wheels revolved three times after the brakes were applied, the stopping distanc

Marrrta [24]

Answer:

188.49

Step-by-step explanation:

use the diameter to find the circumference..

C = d pi or C = 2r pi

when you plug in 20, you get 62.83

now take that, and multiply it by 3, because the wheels went around three times.

62.83 * 3 = 188.49 inches

i hope this was helpful to you!

stay safe!!

:)

4 0

3 years ago

In 1859, 24 rabbits were released into the wild in Australia, where they had no natural predators. Their population grew exponen

Mashcka [7]

Answer:

a) P' = P

$P(t) = 24e^{0.693t}$ where t is step of 6 months

b) 7.7 years

c)1064.67 rabbits/year

Step-by-step explanation:

The differential equation describing the population growth is

$\frac{dP}{dt} = P$

Where t is the range of 6 months, or half of a year.

P(t) would have the form of

$P(t) = P_0e^{kt}$

where $P_0 = 24$ is the initial population

After 6 month (t = 1), the population is doubled to 48

$P(1) = 24e^k = 48$

$e^k = 2$

$k = ln(2) = 0.693$

Therefore $P(t) = 24e^{0.693t}$

where t is step of 6 months

b. We can solve for t to get how long it takes to get to a population of 1,000,000:

$24e^{0.693t} = 1000000$

$e^{0.693t} = 1000000 / 24 = 41667$

$0.693t = ln(41667) = 10.64$

$t = 10.64 / 0.693 = 15.35$

So it would take 15.35 * 0.5 = 7.7 years to reach 1000000

c. $P' = P_0ke^{kt}$

We need to resolve for k if t is in the range of 1 year. In half of a year (t = 0.5), the population is 48

$24e^{0.5k) = 48$

$0.5k = ln2 = 0.693$

$k = 1.386$

Therefore, $P' = 1.386*24e^{1.386t}$

At the mid of the 3rd year, where t = 2.5, we can calculate P'

$P' = 1.386*24e^{1.386*2.5} = 1064.67$ rabbits/year

4 0

3 years ago

Which diagram shows lines that must be parallel lines cut by a transversal? 2 horizontal lines are intersected by a third line.

ivanzaharov [21]

Answer:

(A) At the intersection of the first line with the third line, the bottom left angle is 115 degrees. At the intersection of the second line with the third line, the uppercase left angle is 65 degrees.

Step-by-step explanation:

Alternate interior angles are supplementary when parallel lines are crossed by a transversal. The first description seems to be describing alternate interior angles. (See attachment)

_____

<em>Comment on orientation</em>

If the transversal is oriented horizontally, then the descriptions of the angles will be of different angles than assumed here.

8 0

3 years ago

Read 2 more answers

Write a reclusive rule for the sequence, then give the next two numbers in the sequence 6,1,7,8,15,23

vlabodo [156]

Answer:

aₙ = aₙ₋₁ + aₙ₋₂

where:

a₁ = 6

a₂= 1.

Step-by-step explanation:

We have the sequence:

6, 1, 7, 8, 15, 23, ...

Is easy to see that this sequence works as follows:

You take 2 consecutive numbers, and the next number is the sum of these two.

Then we have:

6 + 1 = 7

1 + 7 = 8

7 + 8 = 15

8 + 15 = 23

Then the n-th term is equal to the sum of the (n - 1) term and the (n - 2) term.

This is written as:

aₙ = aₙ₋₁ + aₙ₋₂

Because in the recursive rule needs two previous terms, we need to specify the two first terms of the sequence.

Then we need to write also:

a₁ = 6

a₂= 1.

5 0

3 years ago