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VikaD [51]
2 years ago
10

WAP to enter the time in hours and print the equivalent time in minutes​

Computers and Technology
1 answer:
professor190 [17]2 years ago
7 0

Answer:

How to convert the hours into minutes and seconds?

We know that there are 60 minutes in an hour, and there are 60 seconds in a minute. But here, we only have the value of hours as an input. We have to convert that input into minutes and seconds. So, the formula to convert the hours into minutes and seconds is -

Now, let's see the programs to convert the hours into minutes and seconds.

<em>a program to convert the hours into minutes and seconds in C language :</em>

#include <stdio.h>  void conversion(float hours)  {      double minutes, seconds;        minutes = hours * 60;      seconds = hours * 3600;            printf("There are %lf minutes in %f hours", minutes, hours);      printf("\nThere are %lf seconds in %f hours", seconds, hours);  }    int main()  {      float hours;      printf("Enter the value of hours: ");      scanf("%f", &hours);      conversion(hours);      return 0;  }  

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V125BC [204]

Answer:

The answer is "5 users and 1 block".

Explanation:

In Option a:

Bandwidth total = 1-Gbps \times 1000

                          = 1,000 \ Mbps      

Any User Requirement = 200 \ Mbps

The method for calculating the number of approved users also is:  

Now, calculate the price of each person for overall bandwidth and demands,  

\text{Sponsored user amount} = \frac{\text{Bandwidth total}}{\text{Each user's requirement}}

                                     =\frac{1000}{200}\\\\=\frac{10}{2}\\\\= 5 \ users

In Option b:

\text{blocking probability} = \frac{link}{\text{1-Gbps} = 10^9 \frac{bits}{sec}}

\ let = 0.05 = \frac{100}{20} \\\\\text{blocking probability} = \frac{ 200 \times 10^6}{\frac{100}{20}}

                                = \frac{ 200 \times 10^6 \times 20 }{100}\\\\= \frac{ 2 \times 10^6 \times 20 }{1}\\\\= 40 \times 10^6 \\\\

mean user = 25 \times \frac{1}{20} \\\\

                  = 1.25

max user = \frac{10^9}{40 \times 10^6} \\\\

                = \frac{10^9}{4 \times 10^7} \\\\ = \frac{10^2}{4} \\\\ = \frac{100}{4} \\\\= 25 \\\\ =\ \ 1 \ \ block \\\\

3 0
3 years ago
Create a class named Circle with fields named radius, diameter, and area. Include a constructor that sets the radius to 1 and ca
REY [17]

Answer:

The code for this class is shown in the explanation section

Explanation:

public class Circle {

   private double radius;

   private double diameter;

   private double area;

   public Circle(double radius, double diameter, double area) {

       this.radius = 1;

       this.diameter = diameter;

       this.area = area;

   }

   public void setRadius(double radius) {

       this.radius = radius;

       diameter = radius*2;

       area= Math.PI*(radius*radius);

   }

   public double getRadius() {

       return radius;

   }

}

6 0
3 years ago
Which of the following is a disadvantage of using face-to-face communication over other communication channels? A) There is lag
Tems11 [23]

Answer:

Option B is correct.

Explanation:

The drawback to choosing face-to-face contact across certain platforms of interactions is that it is always impracticable to plan a schedule for face-to-face conversation because mostly the time of both participants should not be the same, sometime the one person wait for the other person or the other person wait for 1st one.

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luda_lava [24]

Answer:

// Program is written in C++ Programming Language

// Comments are used for explanatory purpose

// Program starts here

#include<iostream>

using namespace std;

int main ()

{

// Declare Variable

int selection;

// Prompt user to make a selection of medium between air, water or steel.

cout<<"Make Selection"<<'\n'<<"Press 1 for Air"<<'\n'<<"Press 2 for Water"<<'\n'<<"Press 3 for Steel";

cin>>selection;

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cout<<"You selected Air"<<'\n';

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}

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}

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return 0;

}

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