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2 years ago

Which value is equivalent to the expression 3^2 × 3^3?

Mathematics

1 answer:

Aleks [24]2 years ago

8 0

Answer:

243

Step-by-step explanation:

3^2 x 3^3 is the same as 3x3 x 3x3x3 which is 9x27 which is 243

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Example 3: A rectangular garden has a length of (x + 4) feet and a width of (x+3) feet.

VMariaS [17]

9514 1404 393

Answer:

4x +14 . . . feet

Step-by-step explanation:

The perimeter is given by ...

P = 2(L+W)

P = 2((x +4) +(x +3)) = 2(2x +7)

P = 4x +14

The perimeter of the garden is 4x +14 feet.

3 0

3 years ago

11. Mr. Dawley bought 2 Hydroflask water bottles at $2.49 each

Lapatulllka [165]

Answer:

$10.23

Step-by-step explanation:

2 hydroflasks for 2.49 dollars each is equal to $4.98 and 3 Rubik's cubes for 1.75 dollars each is equal to $5.25 and when you add both of them, you get $10.23

5 0

2 years ago

Read 2 more answers

Producing a musical costs $88,000 plus $5900 per performance. one sold out performance earns $7500 in revenue. If every performa

yan [13]

X = # of perfomances

y = total amount of money

Income: y = 7500x

Expense: y = 5900x + 88000

Substitution:

7500x = 5900x + 88000

1600x = 88000

x = 55

y = 7500(55) = $412,500

55 performances are needed to break-even.

5 0

2 years ago

A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther

mariarad [96]

<h2>Answer:</h2>

Recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

$a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\$

Therefore, on checking, we observe that,

$a_{n}=a_{n-1}+(n-1)^{2}$

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

At,

n = 1

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0$

which is true.

At,

n = 2

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1$

Which is also true.

At,

n = 3

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5$

Which is true.

At,

n = 4

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14$

This is also true at the given value of 'n'.

Therefore, the recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

3 0

2 years ago

6x + 5y = 16 −6x + 7y = 80

Kobotan [32]

The equation of the line in point-slope form is equal to

The equation of the line in standard form is equal to

step 1

Find the slope m

Let

step 2

convert to standard form

6 0

3 years ago