Answer:
Perimeter of rectangle 1=4x+4
Perimeter of rectangle 2=4x+4
Step-by-step explanation:
Two squares with the same dimension
Square 1: let length=x
Square 2: let length=x
Since they have same dimensions
He added two inches to the length of square 1 to make it a rectangle
Rectangle 1: width=x, length=x+2
Perimeter=2(l+w)
=2{(x+2)+x}
=2(x+2+x)
=2(2x+2)
=4x+4
He added two inches to the width of square 2 to make it a rectangle
Rectangle 2: length=x, width=x+2
Perimeter=2(l+w)
=2{(x+(x+2)}
=2(x+x+2)
=2(2x+2)
=4x+4
The two rectangles have equal perimeter
The answer is -9 and 4.
-9×4 = -36.
-9+4 =-5
The surface area is the area of the outside of a 3D shape for example, let’s say you have a cube, a cube has 6 sides, so you have to find the area of each side and then add it up, since it’s a cube you would technically have to find the area of one side and then just multiply it by 6, that would be the easiest way to do it
Hope I helped!
2nd one
5th one
are both correct
