There are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned from 14 volunteers.
Given that a school dance committee has 14 volunteers and each dance requires 3 volunteers at the door, 5 volunteers on the floor and 6 on floaters.
We are required to find the number of ways in which the volunteers can be assigned.
Combinations means finding the ways in which the things can be choosed to make a new thing or to do something else.
n=n!/r!(n-r)!
Number of ways in which the volunteers can be assigned is equal to the following:
Since 2 have not been assigned so left over volunteers are 14-2=12 volunteers.
Number of ways =14
=14!/12!(14-12)!
=14!/12!*2!
=14*13/2*1
=91 ways
Hence there are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned.
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Answer: 296 or 592
Step-by-step explanation:
Answer:
i am on this exact question and i am confused myself because it seems like the answer should be "180 degree rotation with a translation of 5 units to the right" but that is not an option :/ so my best guess is either A or D hope this helps at all
Step-by-step explanation:
Answer:
16v
Step-by-step explanation:
3x + 11 = 4x - 5
11+5 = 4x -3x
x = 16
I hope im right!!
Answer:
The margin of error will be "0.65". A further explanation is provided below.
Step-by-step explanation:
The given values are:
n = 343
x = 110
At 99% confidence level,
%
then,
or,
Now,
The point estimate will be:
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or,
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The margin of error will be:
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On substituting the above values, we get
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hence,
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