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vichka [17]
2 years ago
11

plsss help with these math questions i will give brainliest to the best and clear answer that has an explanation!!!

Mathematics
1 answer:
erma4kov [3.2K]2 years ago
7 0

For problem one she starts off earning 10.24 dollars per hour. She receives a raise of 1.60 dollars. So first you have to add both 10.24 and 1.60 together to find out how much more she is payed. 10.24+1.60=12.04. She works 22.25 hours. It would take forever to add 12.04 22 and a quarter times so you multiply them. 12.04*22.25=267.89. So she would earn 267.89 dollars from working 22.25 hours.

For problem two you would start off by dividing 3/4 (the amount of pizza) by 5 (the five people) because when you do this it will give you the equal amount of pizza that each person can have. You get 0.15 which is equal to 3/20. So each person will get 3/20 of the 3/4 of the pizza that are left. (To simplify it the answer is 3/20) you can check your work by doing 3*5 which is 15. Make this the numerator and it’s 15/20. 15/20=3/4.

For the third problem you start off by putting aside the .25 of an ounce. Take the 3 ounces and multiply it by the cost per ounce 3.56. 3*3.56=10.68. Now that you have figured out how much 3 ounces cost out that aside. Now for the .25 of an ounce. Since .25 goes into one four times you do 3.56/4. It’s 0.89. This is how much it costs per .25 of an ounce. After that you add 10.68+0.89. It’s 11.57. To finish the problem you have to subtract 11.57 from 20 dollars. 20.00-11.57=8.43. The teacher receives $8.43 in change.

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3 years ago
Element X decays radioactively with a half life of 12 minutes. If there are 200 grams of Element X, how long, to the nearest ten
Semenov [28]

Answer:

It would take 24 minutes for the element to decay to 50 grams

Step-by-step explanation:

The equation for the amount of the element present, after t minutes, is:

Q(t) = Q(0)e^{-rt}

In which Q(X) decays radioactively with a half life of 12 minutes.(0) is the initial amount and r is the rate it decreases.

Half life of 12 minutes

This means that Q(12) = 0.5Q(0)

So

Q(t) = Q(0)e^{-rt}

0.5Q(0) = Q(0)e^{-12r}

e^{-12r} = 0.5

\ln{e^{-12r}} = \ln{0.5}

-12r = \ln{0.5}

12r = -\ln{0.5}

r = -\frac{\ln{0.5}}{12}

r = 0.05776

If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?

This is t when Q(t) = 50. Q(0) = 200.

Q(t) = Q(0)e^{-rt}

50 = 200e^{-0.05776t}

e^{-0.05776t} = 0.25

\ln{e^{-0.05776t}} = \ln{0.25}

-0.05776t = \ln{0.25}

0.05776t = -\ln{0.25}

t = -\frac{\ln{0.25}}{0.05776}

t = 24

It would take 24 minutes for the element to decay to 50 grams

6 0
3 years ago
90,88,88,87,84,95,90,80,98,and 100
Nitella [24]
In order to find the median the 1st thing I would do is put the number in order
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until you get 1 number in the middle left (Since theirs 2 numbers in the middle add them up and divide by two ) 88+90=178   178/2=89
Median = 89 

Now in Order to find the mean add up all the numbers and divide by however many numbers their are 
You should get 900 then divide by 10 because their were 10 numbers 

So Median=89 &  Mean=90 
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