Answer:
See explanation.
Step-by-step explanation:
Let us first analyze some principle theory. By definition we know that the velocity (
) is a function of a distance (
) covered in some time (
), whilst acceleration (
) is the velocity achieved in some time. These can also been expressed as:
and 
We also know that both velocity and acceleration are vectors (therefore they are characterized by both a magnitude and a direction). Finally we know that given a position vector we can find the <u>velocity and the acceleration</u>, by differentiating the vector with respect to time, once and twice, respectively.
Let us now solve our problem. Here we are givine the Position vector of a particle P (in two dimensional space of
) as:
Eqn.(1)
Let us solve.
<u>Part (a) Velocity: </u><u>we need to differentiate Eqn.(1) with respect to time as:</u>
Eqn.(2)
<u>Part (b) Acceleration: </u><u>we need to differentiate Eqn.(2) with respect to time as:</u>
<u />
<u />
<u />
Thus the expressions for the velocity and the acceleration of particle P in terms of t are
and 
Answer:
True
Step-by-step explanation:
hope it helps .............
Answer:
The value of n is 5/3 .
Step-by-step explanation:
You have to apply Indices Law,
![\sqrt[n]{a} \: ⇒ \: {a}^{ \frac{1}{n} }](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Ba%7D%20%20%5C%3A%20%E2%87%92%20%5C%3A%20%20%7Ba%7D%5E%7B%20%5Cfrac%7B1%7D%7Bn%7D%20%7D%20)

So for this question :
![{( \sqrt[3]{3}) }^{5}](https://tex.z-dn.net/?f=%20%7B%28%20%5Csqrt%5B3%5D%7B3%7D%29%20%7D%5E%7B5%7D%20)



Answer:
-12
Step-by-step explanation:
If you lose 3 yards for EACH of the 4 plays, than the equation is -3x4=-12
Answer:
t = time in decimal years; e.g., 6 months is calculated as 0.5 years. Divide your partial year number of months by 12 to get the decimal years.
Step-by-step explanation: