Solution-
First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I
Total number of ways of selection of 4 letters from 9 alphabets = 9C4
=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126
The number of ways of arranging these 4 numbers = 4! = 24
∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024
∴ option number 2 is correct.
Use the formula SA=a+1/2ps
a=area of the base
p= perimeter of the base
s= slant height
Answer:
Step-by-step explanation:
B
The following function would be a or d
Answer:
(x + 3)(x + 5)
Step-by-step explanation:
The given expression is x^2 +8x + 15
Now find the factor of 15 such that when you add the factors, we have to get 8
The right factors of 15.
5 * 3 = 15
5 + 3 = 8
The right factors are 3 and 5.
x^2 + 8x + 15 = (x + 3)(x + 5)
Therefore, x^2 + 8x + 15 = (x + 3)(x + 5)
Thank you.