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1 year ago

How do I solve it? URGANT!!!

Mathematics

1 answer:

defon1 year ago

5 0

Answer:

Step-by-step explanation:

KL = JK, so ΔJKL is an isocesles triangle, then m∠J = m∠L

KL is a tangent line, so ∠JKL = 90°,

so m∠J = 45°

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Please simplify this expression ! Show your work and please answer this !!

tangare [24]

Answer:

18q^2 - 52q + 32

Step-by-step explanation:

We can use the Distributive Property to solve this.

(2q-4)(9q-8)

2q(9q) + 2q(-8) + -4(9q) + -4(-8)

18q^2 - 16q - 36q + 32

18q^2 - 52q + 32

18q^2 - 52q + 32

6 0

3 years ago

. What are the equation and slope of the line that is parallel to the y-axis and goes through the point (1,-2)?

Brrunno [24]

The answer:

x = 1

Explanation:

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8 0

2 years ago

Given that the expression 2x^3 + mx^2 + nx + c leaves the same remainder when divided by x -2 or by x+1 I prove that m+n =-6

Alla [95]

Given:

The expression is:

$2x^3+mx^2+nx+c$

It leaves the same remainder when divided by x -2 or by x+1.

To prove:

$m+n=-6$

Solution:

Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).

Let the given polynomial is:

$P(x)=2x^3+mx^2+nx+c$

It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that

$P(2)=P(-1)$ ...(i)

Substituting $x=-1$ in the given polynomial.

$P(-1)=2(-1)^3+m(-1)^2+n(-1)+c$

$P(-1)=-2+m-n+c$

Substituting $x=2$ in the given polynomial.

$P(2)=2(2)^3+m(2)^2+n(2)+c$

$P(2)=2(8)+m(4)+2n+c$

$P(2)=16+4m+2n+c$

Now, substitute the values of P(2) and P(-1) in (i), we get

$16+4m+2n+c=-2+m-n+c$

$16+4m+2n+c+2-m+n-c=0$

$18+3m+3n=0$

$3m+3n=-18$

Divide both sides by 3.

$\dfrac{3m+3n}{3}=\dfrac{-18}{3}$

$m+n=-6$

Hence proved.

7 0

2 years ago

I need help with this one pls!

Alex73 [517]

Hi there!

$\large\boxed{b = \frac{a}{ac - 1}}$

We can begin by making each fraction have a common denominator:

If we make each have a common denominator of ab, we get:

$\frac{b}{ab} + \frac{a}{ab} = c$

Simplify:

$\frac{a + b}{ab} = c$

Multiply both sides by ab:

$a + b = cab$

Move b to the opposite side:

$a = cab - b$

Factor out b:

$a = b(ac - 1)$

Divide by (ac - 1):

$\frac{a}{ac - 1} = b$

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3 years ago

Which equation is a linear function??

Sever21 [200]

The third equation is linear

6 0

2 years ago