Question

Find the value of x in the triangle below

Answer 1

Answer:

• √80 (Option A)

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Step-by-step explanation:

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• This is Right Angled Triangle.

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We'll solve this using the Pythagorean Theorem.

Let,

• x be AC, where AC is the Hypotenuse.

• 4 be AB, where AB is the Perpendicular.

• 8 be BC, where BC is the Base

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We know that,

${ \longrightarrow \pmb{ \qquad (AC) {}^{2} = (AB) {}^{2} +( BC) {}^{2} }}$

${ \longrightarrow \sf{ \qquad (x) {}^{2} = (4) {}^{2} +( 8) {}^{2} }}$

${ \longrightarrow \sf{ \qquad (x) {}^{2} = 16 +64 }}$

${ \longrightarrow \sf{ \qquad (x) {}^{2} = 80 }}$

${ \longrightarrow \it\pmb{ \qquad x {} = \sqrt{80} }}$

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Therefore,

• The value of x is √80

Answer 2

The figure is a right angled triangle , where the value 4 is perpendicular , 8 is base and x is hypotenuse.

So, By Pythagoras theorem

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$x {}^{2} = 4 {}^{2} + 8 {}^{2}$

$x = \sqrt{16 + 64}$

$x = \sqrt{80}$