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zheka24 [161]
2 years ago
11

Which inequality does the graph represent (pls I’m HORRIBLE at number lines so please answer both if possible, Ty)

Mathematics
1 answer:
notsponge [240]2 years ago
3 0

Answer:

For #11 it is X≥-2.  For #12 it is X<-1 I think

Step-by-step explanation:

I hope this helps you and please mark me as brainliest

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Irrational

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Verify sine law by taking triangle in 4 quadrant<br>Explain with figure.<br>​
Ksivusya [100]

Proof of the Law of Sines

The Law of Sines states that for any triangle ABC, with sides a,b,c (see below)

a

 sin  A

=

b

 sin  B

=

c

 sin  C

For more see Law of Sines.

Acute triangles

Draw the altitude h from the vertex A of the triangle

From the definition of the sine function

 sin  B =

h

c

    a n d        sin  C =

h

b

or

h = c  sin  B     a n d       h = b  sin  C

Since they are both equal to h

c  sin  B = b  sin  C

Dividing through by sinB and then sinC

c

 sin  C

=

b

 sin  B

Repeat the above, this time with the altitude drawn from point B

Using a similar method it can be shown that in this case

c

 sin  C

=

a

 sin  A

Combining (4) and (5) :

a

 sin  A

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b

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- Q.E.D

Obtuse Triangles

The proof above requires that we draw two altitudes of the triangle. In the case of obtuse triangles, two of the altitudes are outside the triangle, so we need a slightly different proof. It uses one interior altitude as above, but also one exterior altitude.

First the interior altitude. This is the same as the proof for acute triangles above.

Draw the altitude h from the vertex A of the triangle

 sin  B =

h

c

      a n d          sin  C =

h

b

or

h = c  sin  B       a n d         h = b  sin  C

Since they are both equal to h

c  sin  B = b  sin  C

Dividing through by sinB and then sinC

c

 sin  C

=

b

 sin  B

Draw the second altitude h from B. This requires extending the side b:

The angles BAC and BAK are supplementary, so the sine of both are the same.

(see Supplementary angles trig identities)

Angle A is BAC, so

 sin  A =

h

c

or

h = c  sin  A

In the larger triangle CBK

 sin  C =

h

a

or

h = a  sin  C

From (6) and (7) since they are both equal to h

c  sin  A = a  sin  C

Dividing through by sinA then sinC:

a

 sin  A

=

c

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a

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7 0
3 years ago
PLS HELP WILL GIVE BRAINLIEST :)
Rus_ich [418]

Step-by-step explanation:

the slope intercept form is

y = ax + b

"a" being the slope, "b" being the y- intercept (which is the y-value when x = 0).

the slope here :

in the table x is always increasing by 2.

and y is always investing by 1.

so, the slope is 1/2

the y-intercept :

we need to find the y-value for x = 0.

but we don't have a data point with x = 0 in the table.

so, we have to extend the structure of the table to the left.

x decreases by 2 (making it 0), and y decreases by 1 (making it -1).

therefore, the y- intercept (b) is -1.

and the line equation is

y = (1/2)x - 1

not sure about "the other method".

there is the point-slope form of the equation :

y - y1 = a(x - x1)

again with "a" begin the slope, and (x1, y1) being a point on the line.

if we get the y-intercept in the table, then this point is (0, y1).

and the equation would be

y - y1 = ax

in our case

y + 1 = (1/2)x

and another method ?

sometimes people write

nx + my = c

in our case starting with the original equation

y = (1/2)x - 1

2y = x - 2

-x + 2y = -2

x - 2y = 2

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2 years ago
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lesya692 [45]
I don’t see the picture if I see it I can help you tho
5 0
2 years ago
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