2 answers:
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Hello there,
Well we are going to start off with the equation to find the slope based on the given points:
Now using the two given points we are going to plug in and solve:
=
=
From this you know that is the slope of the equation. However, to find the y-intercept we are going to use y = mx+ b and plug in one of the points to solve:
(-14) = (-22) + b
(-14) = (-11) + b
-3 = b
That means that the y-intercept is at (0, -3). Lastly, we are just going to plug all this into the slope-intercept form:
y = - 3
Hope I helped,
Amna
Answer:
Follows are the solution to the given point:
Step-by-step explanation:
In point a:
¬∃y∃xP (x, y)
∀x∀y(>P(x,y))
In point b:
¬∀x∃yP (x, y)
∃x∀y ¬P(x,y)
In point c:
¬∃y(Q(y) ∧ ∀x¬R(x, y)) ∀y(> Q(y) V ∀ ¬ (¬R(x,y)))
∀y(¬Q(Y)) V ∃xR(x,y) )
In point d:
¬∃y(∃xR(x, y) ∨ ∀xS(x, y))
∀y(∀x>R(x,y)) ∃x>s(x,y))
In point e:
¬∃y(∀x∃zT (x, y, z) ∨ ∃x∀zU (x, y, z))
∀y(∃x ∀z)>T(x,y,z) ∀x ∃z> V (x,y,z))